题目源:http://agc012.contest.atcoder.jp/tasks/agc012_b
存边的方法我就不说了
这题的做法说白了就是强暴力+优化
染色从后往前染(不解释)
对于每个点,标记该点已染色的最大范围,搜到该点时,若还需染色的范围比标记小就不用染下去了
下面贴代码,注意数组要开两倍
type arr=array[0..200001]of longint;
var n,q,m,i,j,a,b:longint;
v,d,c,max,cl,head,next,start,endd:arr;
bb,bc:array[0..200001]of boolean;
procedure dfs(k,dis,col:longint);
var i:longint;
begin
bb[k]:=true;
if(max[k]>=dis)and(bc[k])then begin
bb[k]:=false;
exit;
end;
max[k]:=dis;
if not bc[k]then begin
cl[k]:=col;
bc[k]:=true;
end;
if dis>0 then for i:=start[k] to endd[k] do
if not bb[next[i]]then dfs(next[i],dis-1,col);
bb[k]:=false;
end;
procedure sort(l,r:longint);
var i,j,x,y:longint;
begin
i:=l;j:=r;x:=head[(l+r) div 2];
repeat
while head[i]do inc(i);
while xdo dec(j);
if not(i>j) then begin
y:=head[i];head[i]:=head[j];head[j]:=y;
y:=next[i];next[i]:=next[j];next[j]:=y;
inc(i);j:=j-1;
end;
until i>j;
if lthen sort(l,j);
if ithen sort(i,r);
end;
begin
readln(n,m);
fillchar(cl,sizeof(cl),0);
fillchar(max,sizeof(max),0);
fillchar(bb,sizeof(bb),false);
fillchar(bc,sizeof(bc),false);
for i:=1 to m do begin
readln(a,b);
head[i]:=a;head[i+m]:=b;
next[i]:=b;next[i+m]:=a;
end;
m:=m*2;sort(1,m);start[head[1]]:=1;
for i:=2 to m do if head[i]<>head[i-1]then begin
endd[head[i-1]]:=i-1;
start[head[i]]:=i;
end;
endd[head[m]]:=m;
readln(q);
for i:=q downto 1 do readln(v[i],d[i],c[i]);
for i:=1 to q do dfs(v[i],d[i],c[i]);
for i:=1 to n do writeln(cl[i]);
end.