Find the sum of all left leaves in a given binary tree.
Example:
3
/ \
9 20
/ \
15 7
There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.
class Solution {
public:
int sumOfLeftLeaves(TreeNode* root) {
if (root == nullptr) return 0;
if (root->left) {
if (root->left->left == nullptr && root->left->right == nullptr) {
return root->left->val + sumOfLeftLeaves(root->right);
} else {
return sumOfLeftLeaves(root->left) + sumOfLeftLeaves(root->right);
}
} else {
return sumOfLeftLeaves(root->right);
}
}
};