牛客掉坑指南

1.格式错误:您的程序输出的格式不符合要求（比如空格和换行与要求不一致）case通过率为0.00%

题目链接

广州大学第十四届ACM大学生程序设计竞赛 A题 攀登

初始代码

#include 
#include 
using namespace std;
class Madeline {
     
private:
	int n = 0;
	int k[100] = {
      0 };
	string t[100] = {
      "/0" };
	string s[100] = {
      "/0" };
public:
	void Madeline1();
	void Madeline2();
};
void Madeline::Madeline1() {
     
	cin >> n;
	string x, y;
	for (int i = 0; i < n; i++) {
     
		cin >> t[i];
		if (t[i] != "QuickDrop" && t[i] != "Squat" && t[i] != "Grasp" && t[i] != "Jump")
			cin >> s[i];
		if (t[i] == "QuickDrop")		    k[i] = 1;
		else if (t[i] == "Squat")			k[i] = 1;
		else if (t[i] == "Grasp")			k[i] = 2;
		else if (t[i] == "Jump")			k[i] = 3;
		else if (t[i] == "left" && s[i] == "Walk")		k[i] = 4;
		else if (t[i] == "right" && s[i] == "Walk")		k[i] = 5;
		else if (t[i] == "leftup" && s[i] == "Dash")		k[i] = 6;
		else if (t[i] == "up" && s[i] == "Dash")			k[i] = 7;
		else if (t[i] == "rightup" && s[i] == "Dash")	k[i] = 8;
		else if (t[i] == "left" && s[i] == "Dash")		k[i] = 9;
		else if (t[i] == "right" && s[i] == "Dash")		k[i] = 10;
		else if (t[i] == "leftdown" && s[i] == "Dash")	k[i] = 11;
		else if (t[i] == "down" && s[i] == "Dash")		k[i] = 12;
		else if (t[i] == "rightdown" && s[i] == "Dash")	k[i] = 13;
	}
	cout << endl; //出错原因，多余
}
void Madeline::Madeline2() {
     
	int a = 0;
	for (int i = 0; i < n; i++) {
     
		a = k[i];
		switch (a) {
     
		case 1: cout << "down" << endl;					break;
		case 2: cout << "Z" << endl; 					break;
		case 3: cout << "C" << endl; 					break;
		case 4: cout << "left" << endl; 				break;
		case 5: cout << "right" << endl;  				break;
		case 6: cout << "left up X" << endl;  		    break;
		case 7: cout << "up X" << endl;  				break;
		case 8: cout << "right up X" << endl;  			break;
		case 9: cout << "left X" << endl; 				break;
		case 10: cout << "right X" << endl; 			break;
		case 11: cout << "left down X" << endl; 		break;
		case 12: cout << "down X" << endl; 				break;
		case 13: cout << "right down X" << endl;  		break;
		}
	}
};
int main() {
     
	Madeline m;
	m.Madeline1();
	m.Madeline2();
	return 0;
}

提交：

出错原因

• 第36行多了句

cout << endl;

• 对牛客的编译环境不了解，不知道自测的用法
  
  

更改

删去第36行的

cout<<endl;

2.段错误:您的程序发生段错误，可能是数组越界，堆栈溢出（比如，递归调用层数太多）等情况引起case通过率为0.00%

代码

#include 
#include 
using namespace std;
class Madeline {
     
private:
	int n = 0;
	int k[100] = {
      0 };
	string t[100] = {
      "/0" };
	string s[100] = {
      "/0" };
public:
	void Madeline1();
	void Madeline2();
};
void Madeline::Madeline1() {
     
	cin >> n;
	string x, y;
	for (int i = 0; i < n; i++) {
     
		cin >> t[i];
		if (t[i] != "QuickDrop" && t[i] != "Squat" && t[i] != "Grasp" && t[i] != "Jump")
			cin >> s[i];
		if (t[i] == "QuickDrop")		    k[i] = 1;
		else if (t[i] == "Squat")			k[i] = 1;
		else if (t[i] == "Grasp")			k[i] = 2;
		else if (t[i] == "Jump")			k[i] = 3;
		else if (t[i] == "left" && s[i] == "Walk")		k[i] = 4;
		else if (t[i] == "right" && s[i] == "Walk")		k[i] = 5;
		else if (t[i] == "leftup" && s[i] == "Dash")		k[i] = 6;
		else if (t[i] == "up" && s[i] == "Dash")			k[i] = 7;
		else if (t[i] == "rightup" && s[i] == "Dash")	k[i] = 8;
		else if (t[i] == "left" && s[i] == "Dash")		k[i] = 9;
		else if (t[i] == "right" && s[i] == "Dash")		k[i] = 10;
		else if (t[i] == "leftdown" && s[i] == "Dash")	k[i] = 11;
		else if (t[i] == "down" && s[i] == "Dash")		k[i] = 12;
		else if (t[i] == "rightdown" && s[i] == "Dash")	k[i] = 13;
	}
}
void Madeline::Madeline2() {
     
	int a = 0;
	for (int i = 0; i < n; i++) {
     
		a = k[i];
		switch (a) {
     
		case 1: cout << "down" << endl;					break;
		case 2: cout << "Z" << endl; 					break;
		case 3: cout << "C" << endl; 					break;
		case 4: cout << "left" << endl; 				break;
		case 5: cout << "right" << endl;  				break;
		case 6: cout << "left up X" << endl;  		    break;
		case 7: cout << "up X" << endl;  				break;
		case 8: cout << "right up X" << endl;  			break;
		case 9: cout << "left X" << endl; 				break;
		case 10: cout << "right X" << endl; 			break;
		case 11: cout << "left down X" << endl; 		break;
		case 12: cout << "down X" << endl; 				break;
		case 13: cout << "right down X" << endl;  		break;
		}
	}
};
int main() {
     
	Madeline m;
	m.Madeline1();
	m.Madeline2();
	return 0;
}

提交：

出错原因

• 不符合题目的测试用例

	int k[100] = {
      0 };
	string t[100] = {
      "/0" };
	string s[100] = {
      "/0" };

更改

int k[10000] = {
      0 };
string t[10000] = {
      "/0" };
string s[10000] = {
      "/0" };

题目链接

广州大学第十四届ACM大学生程序设计竞赛 A题 攀登