仿射密码的加密解密

因为加密的为英文字母以及数字,所以模数选择26+10=36.
再选一个k1为一个与36互素的数字.
再任意选一个k2
求除k1在模36下的逆元k3.(欧几里得除法,代码也可实现,这里没写,直接给出)
加密为: c=(k1*m+k2)mod36
解密为: m=((c-k2)*k3)mod36

代码

package com.jingfei.Encryptoin;

import java.lang.reflect.Array;
import java.util.Arrays;
import java.util.Scanner;



public class FangShe {
    //加密JIINGFEI03163079
    public static final int N = 36;
    public static final int K1 = 79;//79与36互素
    public static final int K2 = 79;
    public static final int k3 = 31;
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("请输入你要加密的字符串:");
        String m1 =sc.nextLine();//接收输入的字符串
        m1 = m1.toString().toUpperCase();//输入的小写全部变大写
        System.out.println(m1);
        char[] inputchars = new char[m1.length()];
        for (int i =0;i

请输入你要加密的字符串:
worldHELLO1234
加密后为:
R7SM2U9MM7QX4B
解密后为:
WORLDHELLO1234

Process finished with exit code 0

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谢谢!