HDU A + B Problem II

A + B Problem II

Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other)

Total Submission(s) : 8   Accepted Submission(s) : 3

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

 

Sample Input

    
    
    
    

     
     
     
     2
1 2
112233445566778899 998877665544332211

    
    
    
    

 

Sample Output

    
    
    
    

     
     
     
     Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

    
    
    
    

 

import java.io.*;    
import java.math.*;    
import java.util.*;    
import java.text.*;   
  
public class Main{  
    public static void main(String[] args)  
    {  
        Scanner cin = new Scanner (new BufferedInputStream(System.in));  
        int times=1;  
        int T;  
        T=cin.nextInt();  
        while(T!=0)  
        {  
            BigInteger a;  
            BigInteger b;  
            a=cin.nextBigInteger();  
            b=cin.nextBigInteger();  
            System.out.println("Case "+ (times++)+":");  
            System.out.println(a + " + " + b + " = " + a.add(b));  
            if(T!=1) System.out.println("");  
            T--;  
        }  
          
    }  
}