----------------------------------------------------------------------------------
-- Author : htl258(Tony)
-- Date : 2010-06-04 08:21:56
-- Version: Microsoft SQL Server 2008 (RTM) - 10.0.1600.22 (Intel X86)
-- Jul 9 2008 14:43:34
-- Copyright (c) 1988-2008 Microsoft Corporation
-- Developer Edition on Windows NT 5.1
-- Blog : http://blog.csdn.net/htl258
-- Subject: 变通解决SQL视图中排序异常问题
----------------------------------------------------------------------------------
--> 生成测试数据表: [tb]
IF OBJECT_ID('[tb]') IS NOT NULL
DROP TABLE [tb]
GO
CREATE TABLE [tb] ([a] [int],[b] [nvarchar](10),[c] [nvarchar](10))
INSERT INTO [tb]
SELECT '3','c','测' UNION ALL
SELECT '1','a','试' UNION ALL
SELECT '5','e','视' UNION ALL
SELECT '6','f','图' UNION ALL
SELECT '2','d','排' UNION ALL
SELECT '4','b','序'
--SELECT * FROM [tb]
-->SQL查询如下:
--1.正常的顺序:
IF OBJECT_ID('vw_TestOrder') >0
DROP VIEW vw_TestOrder
GO
CREATE VIEW vw_TestOrder
AS
SELECT * FROM tb
GO
SELECT * FROM vw_TestOrder
/*
a b c
----------- ---------- ----------
3 c 测
1 a 试
5 e 视
6 f 图
2 d 排
4 b 序
(6 行受影响)
*/
--2.加上TOP 100 PERCENT后的排序
IF OBJECT_ID('vw_TestOrder') >0
DROP VIEW vw_TestOrder
GO
CREATE VIEW vw_TestOrder
AS
SELECT TOP 100 PERCENT *
FROM tb
GO
SELECT * FROM vw_TestOrder
/*
a b c
----------- ---------- ----------
3 c 测
1 a 试
5 e 视
6 f 图
2 d 排
4 b 序
(6 行受影响)
*/
--3.变通处理后的排序
IF OBJECT_ID('vw_TestOrder') >0
DROP VIEW vw_TestOrder
GO
CREATE VIEW vw_TestOrder
AS
WITH t AS
(
SELECT * FROM tb
)
SELECT TOP (SELECT COUNT(1) FROM t)
*
FROM t
ORDER BY a
GO
SELECT * FROM vw_TestOrder
/*
a b c
----------- ---------- ----------
1 a 试
2 d 排
3 c 测
4 b 序
5 e 视
6 f 图
(6 行受影响)
*/
--下面是为一个需求贴而写,链接:http://topic.csdn.net/u/20100604/06/77111376-863a-4c03-8844-69f1e9bb8ed0.html?62587
----------------------------------------------------------------------------------
-- Author : htl258(Tony)
-- Date : 2010-06-04 08:16:38
-- Version: Microsoft SQL Server 2008 (RTM) - 10.0.1600.22 (Intel X86)
-- Jul 9 2008 14:43:34
-- Copyright (c) 1988-2008 Microsoft Corporation
-- Developer Edition on Windows NT 5.1
-- Blog : http://blog.csdn.net/htl258
-- Subject: 变通解决SQL视图中排序异常问题
----------------------------------------------------------------------------------
--> 生成测试数据表: [barea]
IF OBJECT_ID('[barea]') IS NOT NULL
DROP TABLE barea
GO
CREATE TABLE barea
(
area_id INT PRIMARY KEY,--地区编号
--layer_code VARCHAR(10) NOT NULL,--分层码
area_name NVARCHAR(10) not null,--地区名称
--full_name NVARCHAR(50) NOT NULL,--全名称
parent_id INT DEFAULT(0),--上级地区编号
order_id INT DEFAULT(0)--排序序号
)
INSERT INTO BAREA VALUES(10,'河南省',0,1)
INSERT INTO BAREA VALUES(1001,'郑州市',10,1)
INSERT INTO BAREA VALUES(1002,'南阳市',10,2)
INSERT INTO BAREA VALUES(100101,'安县',1001,3)
INSERT INTO BAREA VALUES(100201,'红县',1002,4)
INSERT INTO BAREA VALUES(20,'海南省',0,0)
INSERT INTO BAREA VALUES(2001,'海口市',20,1)
GO
-->SQL查询如下
IF OBJECT_ID('v_BOM') IS NOT NULL
DROP VIEW v_BOM
GO
CREATE VIEW v_BOM
AS
WITH t AS
(
SELECT *, full_name = CAST(area_name AS VARCHAR), lvl = 1, CAST(
RIGHT(
100+ROW_NUMBER()OVER(PARTITION BY parent_id ORDER BY area_id), 2
) AS VARCHAR
) layer_code, px = CAST(ROW_NUMBER()OVER(ORDER BY order_id) AS VARBINARY)
FROM barea
WHERE parent_id = 0
UNION ALL
SELECT a.*, CAST(full_name+a.area_name AS VARCHAR), lvl+1, CAST(
layer_code+RIGHT(
100+ROW_NUMBER()OVER(PARTITION BY a.parent_id ORDER BY a.area_id), 2
) AS VARCHAR
), px = CAST(
px+CAST(
ROW_NUMBER()OVER(PARTITION BY a.parent_id ORDER BY a.order_id) AS VARBINARY
) AS VARBINARY
)
FROM barea a, t b
WHERE a.parent_id = b.area_id
)
SELECT TOP (SELECT COUNT(1) FROM t) --主要是这一句
area_id, layer_code, area_name, full_name, parent_id, order_id
FROM t
ORDER BY px
GO
SELECT * FROM v_bom
/*
area_id layer_code area_name full_name parent_id order_id
----------- ------------------------------ ---------- ------------------------------ ----------- -----------
20 02 海南省 海南省 0 0
2001 0201 海口市 海南省海口市 20 1
10 01 河南省 河南省 0 1
1001 0101 郑州市 河南省郑州市 10 1
100101 010101 安县 河南省郑州市安县 1001 3
1002 0102 南阳市 河南省南阳市 10 2
100201 010201 红县 河南省南阳市红县 1002 4
(7 行受影响)
*/