题目:判断打印的 “one” or “two” ?
// 1. 两个普通同步方法,两个线程,标准打印, 打印? //one two
// 2. 新增 Thread.sleep() 给 getOne() ,打印? //one two
public class One {
public static void main(String[] args) {
Demo demo=new Demo();
new Thread(new Runnable() {
@Override
public void run() {
demo.getOne();
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
demo.getTwo();
}
}).start();
}
}
class Demo{
public synchronized void getOne(){
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("one");
}
public synchronized void getTwo(){
System.out.println("two");
}
}
1、2:同步方法的所对象是this,先调用的方法先执行,虽然是两个线程,但是只能有一个同步方法被执行。
// 3. 新增普通方法 getThree() , 打印? //three one two
public class One {
public static void main(String[] args) {
Demo demo=new Demo();
new Thread(new Runnable() {
@Override
public void run() {
demo.getOne();
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
demo.getTwo();
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
demo.getThree();
}
}).start();
}
}
class Demo{
public synchronized void getOne(){
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("one");
}
public synchronized void getTwo(){
System.out.println("two");
}
public void getThree(){
System.out.println("Three");
}
}
3.同步方法不受锁的约束
// 4. 两个普通同步方法,两个 Number 对象,打印? //two one
public class One {
public static void main(String[] args) {
Demo demo=new Demo();
Demo demo1=new Demo();
new Thread(new Runnable() {
@Override
public void run() {
demo.getOne();
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
demo1.getTwo();
}
}).start();
/*new Thread(new Runnable() {
@Override
public void run() {
demo.getThree();
}
}).start();*/
}
}
class Demo{
public synchronized void getOne(){
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("one");
}
public synchronized void getTwo(){
System.out.println("two");
}
/* public void getThree(){
System.out.println("Three");
}*/
}
4.形成线程同步的前提是,多个线程拥有同一把锁,本题创建了两个对象,相当于两把锁了。故:各自执行各自的
//5. 修改 getOne() 为静态同步方法,打印? //two one
public class One {
public static void main(String[] args) {
Demo demo=new Demo();
new Thread(new Runnable() {
@Override
public void run() {
demo.getOne();
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
demo.getTwo();
}
}).start();
/*new Thread(new Runnable() {
@Override
public void run() {
demo.getThree();
}
}).start();*/
}
}
class Demo{
public synchronized static void getOne(){
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("one");
}
public synchronized void getTwo(){
System.out.println("two");
}
/* public void getThree(){
System.out.println("Three");
}*/
}
5.静态的同步方法的锁是类实例,同步方法的锁是this,两个线程拥有不同的锁,所以实现不了同步
// * 6. 修改两个方法均为静态同步方法,一个 Number 对象? //one two
public class One {
public static void main(String[] args) {
Demo demo=new Demo();
new Thread(new Runnable() {
@Override
public void run() {
demo.getOne();
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
demo.getTwo();
}
}).start();
/*new Thread(new Runnable() {
@Override
public void run() {
demo.getThree();
}
}).start();*/
}
}
class Demo{
public synchronized static void getOne(){
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("one");
}
public synchronized static void getTwo(){
System.out.println("two");
}
/* public void getThree(){
System.out.println("Three");
}*/
}
6.都是静态方法,公用一个对象锁(类实力),故可以实现同步
//* 7. 一个静态同步方法,一个非静态同步方法,两个 Number 对象? //two one
public class One {
public static void main(String[] args) {
Demo demo=new Demo();
Demo demo1=new Demo();
new Thread(new Runnable() {
@Override
public void run() {
demo.getOne();
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
demo1.getTwo();
}
}).start();
/*new Thread(new Runnable() {
@Override
public void run() {
demo.getThree();
}
}).start();*/
}
}
class Demo{
public synchronized static void getOne(){
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("one");
}
public synchronized void getTwo(){
System.out.println("two");
}
/* public void getThree(){
System.out.println("Three");
}*/
}
7.不是同一个锁,故不同步
// * 8. 两个静态同步方法,两个 Number 对象? //one two
public class One {
public static void main(String[] args) {
Demo demo=new Demo();
Demo demo1=new Demo();
new Thread(new Runnable() {
@Override
public void run() {
demo.getOne();
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
demo1.getTwo();
}
}).start();
/*new Thread(new Runnable() {
@Override
public void run() {
demo.getThree();
}
}).start();*/
}
}
class Demo{
public synchronized static void getOne(){
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("one");
}
public synchronized static void getTwo(){
System.out.println("two");
}
/* public void getThree(){
System.out.println("Three");
}*/
}
8.静态同步方法的锁是“类实例”,与多少个对象无关
总结:通过上述的代码,可以得出: