Description
Input
Output
Sample Input
Sample Output
HINT
Source
在题面里放大样例…我该说Vani良心?
样例太长了不放进去了
在以前看的课件里见过这题
#include
#include
#include
#include
#include
#define MAXN 1000100
#define lowbit(x) (x&(-x))
#define MAXINT 0x7fffffff
using namespace std;
int n,m,size;
int c[MAXN],ans[MAXN];
void in(int &x)
{
char ch=getchar();x=0;int flag=1;
while (!(ch>='0'&&ch<='9')) flag=ch=='-'?-1:flag,ch=getchar();
while (ch>='0'&&ch<='9') x=x*10+ch-'0',ch=getchar();
}
void add(int x,int delta)
{
for (int i=x;i<=size;i+=lowbit(i)) c[i]=max(c[i],delta);
}
int query(int x)
{
int ret=0;
for (int i=x;i;i-=lowbit(i)) ret=max(ret,c[i]);
return ret;
}
void init(int x)
{
for (int i=x;i<=size;i+=lowbit(i)) c[i]=0;
}
struct Query
{
int opt,x,y,id;
bool operator <(const Query& a)const
{
return x==a.x?idxx;
}
}q[MAXN],newq[MAXN];
void solve(int l,int r)
{
int mid=(l+r)>>1,tp1=l,tp2=mid+1;
if (l==r) return;
for (int i=l;i<=r;i++)
if (q[i].id<=mid) newq[tp1++]=q[i];
else newq[tp2++]=q[i];
memcpy(q+l,newq+l,sizeof(Query)*(r-l+1));
solve(l,mid);
int i=mid+1,j=l;
for (i=mid+1;i<=r;i++)
if (q[i].opt==2)
{
for (;j<=mid&&q[j].x<=q[i].x;j++)
if (q[j].opt==1) add(q[j].y,q[j].x+q[j].y);
int temp=query(q[i].y);
if (temp) ans[q[i].id]=min(ans[q[i].id],q[i].x+q[i].y-temp);
}
for (i=l;iif (q[i].opt==1) init(q[i].y);
solve(mid+1,r);
tp1=l,tp2=mid+1;
for (i=l;i<=r;i++)
if ((q[tp1]<q[tp2]||tp2>r)&&tp1<=mid) newq[i]=q[tp1++];
else newq[i]=q[tp2++];
memcpy(q+l,newq+l,sizeof(Query)*(r-l+1));
}
int main()
{
in(n);in(m);
for (int i=1;i<=n;i++) scanf("%d%d",&q[i].x,&q[i].y),q[i].id=i,q[i].opt=1,q[i].x++,q[i].y++,size=max(size,max(q[i].x,q[i].y));
for (int i=n+1;i<=n+m;i++) scanf("%d%d%d",&q[i].opt,&q[i].x,&q[i].y),q[i].id=i,q[i].x++,q[i].y++,size=max(size,max(q[i].x,q[i].y));
size++;
for (int i=1;i<=n+m;i++) ans[i]=MAXINT;
sort(q+1,q+n+m+1);solve(1,n+m);
for (int i=1;i<=n+m;i++) q[i].x=size-q[i].x;
sort(q+1,q+n+m+1);solve(1,n+m);
for (int i=1;i<=n+m;i++) q[i].y=size-q[i].y;
sort(q+1,q+n+m+1);solve(1,n+m);
for (int i=1;i<=n+m;i++) q[i].x=size-q[i].x;
sort(q+1,q+n+m+1);solve(1,n+m);
for (int i=1;i<=n+m;i++)
if (ans[i]!=MAXINT) printf("%d\n",ans[i]);
}