用结构体数组存储30名学生的学号,…

# include "stdio.h"
# define N 30
struct fengshu
{
  int chinese;
  int math;
  int english;
  int Clanguage;
};
struct xinxi
{
  int num;
  int ave;
  char name[15];
  char sex;
  struct fengshu score;
};
average(int a, int b, int c, int d)
{
  int sum=0;
  float ave;
  sum=a+b+c+d;
  ave=sum/4.0;
  return(ave);
}

main()
{
  int i,j;
  struct xinxi s[N];
  struct xinxi t;
  for(i=0;i
  {
    printf("请输入第%d个同学的信息:\n",i+1);
    printf("姓名:");
    gets(s[i].name);      

    printf("语文,数学,英语和C语言的成绩(中间用空格分开) :");
    scanf("%d %d %d %d",&s[i].score.chinese,&s[i].score.math,&s[i].score.english,&s[i].score.Clanguage);
    getchar();            
   }
   }   
  for(i=0;i
    s[i].ave=average(s[i].score.chinese,s[i].score.math,s[i].score.english,s[i].score.Clanguage);
  for(i=0;i    for(j=i+1;j       if(s[i].ave>s[j].ave)
        {
           t=s[i];
           s[i]=s[j];
           s[j]=t;
        }
   printf("按平均分排序为:\n");
   for(i=0;i      printf("学号:%d  姓名:%s  性别:%c  语文,数学,英语,C语言成绩:%d %d %d %d   平均成绩:%d  \n",s[i].num,s[i].name,s[i].sex,s[i].score.chinese,s[i].score.math,s[i].score.english,s[i].score.Clanguage,s[i].ave);
}
                 

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