【PAT】A1028. List Sorting (25)

Description:
Excel can sort records according to any column. Now you are supposed to imitate this function.

Input
Each input file contains one test case. For each case, the first line contains two integers N (<=100000) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student’s record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output
For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID’s; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID’s in increasing order.

Sample Input 1
3 1
000007 James 85
000010 Amy 90

000001 Zoe 60

Sample Output 1
000001 Zoe 60
000007 James 85

000010 Amy 90

Sample Input 2
4 2
000007 James 85
000010 Amy 90
000001 Zoe 60

000002 James 98

Sample Output 2
000010 Amy 90
000002 James 98
000007 James 85

000001 Zoe 60

Sample Input 3
4 3
000007 James 85
000010 Amy 90
000001 Zoe 60

000002 James 90

Sample Output 3
000001 Zoe 60
000007 James 85
000002 James 90

000010 Amy 90

//NKW 甲级练习题1007
#pragma warning(disable:4996)
#include 
#include 
#include 
#include 
using namespace std;
const int maxn = 100010;
int c = -1;
struct student{
	char ing[3][10];		//id,name,gread
}stu[maxn];
bool cmp(student a, student b){    //这样写是受到了A1012的影响，看了别的写法觉得分c=1,2,3三种情况写更好
	if (c != 0 && strcmp(a.ing[c], b.ing[c]))
		return strcmp(a.ing[c], b.ing[c]) <= 0;
	else
		return strcmp(a.ing[0], b.ing[0]) < 0;
}
int main(){
	int n;
	scanf("%d %d", &n, &c);
	for (int i = 0; i < n; i++)
		scanf("%s %s %s", stu[i].ing[0], stu[i].ing[1], stu[i].ing[2]);
	c = c - 1;
	sort(stu, stu + n, cmp);
	for (int i = 0; i < n; i++)
		printf("%s %s %s\n", stu[i].ing[0], stu[i].ing[1], stu[i].ing[2]);
	system("pause");
	return 0;
}