Description:
Find the total area covered by two rectilinear rectangles in a 2D plane.
Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.
Example:
Input: A = -3, B = 0, C = 3, D = 4, E = 0, F = -1, G = 9, H = 2
Output: 45
Note:
Assume that the total area is never beyond the maximum possible value of int
解题思路:判断两个矩形是否相离,是则返回两个矩形面积和,否则还要减去相交部分面积。
代码:
class Solution {
public:
int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
int temp = (C-A)*(D-B)+(G-E)*(H-F);
if(E >= C || G <= A || D <= F || B >= H) //两矩形相离
return temp;
temp -= (min(C, G)-max(A, E))*(min(D, H)-max(B, F)); //相交部分面积
return temp;
}
};