Go语言实现十进制转换成二、八、十六进制

原文地址声明：https://blog.csdn.net/qq_23179075/article/details/87085435

package main

import (
	"errors"
	"fmt"
	"strconv"
)

func DecConvertToX(n, num int) (string,error) {
	if n < 0 {
		return strconv.Itoa(n),errors.New("只支持正整数")
	}
	if num != 2 && num != 8 && num != 16 {
		return strconv.Itoa(n),errors.New("只支持二、八、十六进制的转换")
	}
	result := ""
	h:=map[int]string{
		0:"0",
		1:"1",
		2:"2",
		3:"3",
		4:"4",
		5:"5",
		6:"6",
		7:"7",
		8:"8",
		9:"9",
		10:"A",
		11:"B",
		12:"C",
		13:"D",
		14:"E",
		15:"F",
	}
	for ; n > 0; n /= num {
		lsb := h[n % num]
		result = lsb + result
	}
	return result,nil
}
func main() {
	fmt.Println(DecConvertToX(26, 2))
	fmt.Println(DecConvertToX(26, 8))
	fmt.Println(DecConvertToX(26, 16))
}