【LeetCode with Python】 Spiral Matrix

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原题页面： https://oj.leetcode.com/problems/spiral-matrix/
题目类型：
难度评价：★
本文地址： http://blog.csdn.net/nerv3x3/article/details/41628771

Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.

For example,
Given the following matrix:

[
 [ 1, 2, 3 ],
 [ 4, 5, 6 ],
 [ 7, 8, 9 ]
]

You should return [1,2,3,6,9,8,7,4,5].

class Solution:
    # @param matrix, a list of lists of integers
    # @return a list of integers
    def spiralOrder(self, matrix):

        m = len(matrix)
        if 0 == m:
            return [ ]
        n = len(matrix[0])
        if 0 == n:
            return [ ]
        arr = [ ]

        round = (min(m, n) + 1) / 2
        for x in range(0, round):
            for y in range(x, n - x):
                arr.append(matrix[x][y])
            for y in range(x + 1, m - x - 1):
                arr.append(matrix[y][n - x - 1])
            if m - 2 * x > 1:  ###
                for y in range(n - x - 1, x - 1, -1):
                    arr.append(matrix[m - x - 1][y])
            if n - 2 * x > 1:      ###
                for y in range(m - x - 2, x, -1):   ###
                    arr.append(matrix[y][x])
        return arr