POJ 3624 Charm Bracelet

Charm Bracelet

Time Limit: 1000ms

Memory Limit: 65536KB

This problem will be judged on  PKU. Original ID: 3624
64-bit integer IO format: %lld      Java class name: Main

Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi ≤ 400), a 'desirability' factor Di (1 ≤ Di ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).

Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.

 

Input

* Line 1: Two space-separated integers: N and M* Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: Wi and Di

 

Output

* Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints

 

Sample Input

4 6

1 4

2 6

3 12

2 7

Sample Output

23

Source

USACO 2007 December Silver

 

解题：01背包

 

 1 #include <iostream>

 2 #include <cstdio>

 3 #include <cstring>

 4 using namespace std;

 5 int dp[12900],w[3500],d[3500],n,m;

 6 int main(){

 7     while(~scanf("%d %d",&n,&m)){

 8         for(int i = 0; i < n; ++i)

 9             scanf("%d %d",w+i,d+i);

10         memset(dp,0,sizeof dp);

11         for(int i = 0; i < n; ++i)

12             for(int j = m; j >= w[i]; --j)

13                 dp[j] = max(dp[j],dp[j-w[i]] + d[i]);

14         printf("%d\n",dp[m]);

15     }

16     return 0;

17 }

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