【python】获取目录下的最新文件夹/文件

def new_report(test_report):
    lists = os.listdir(test_report)                                    #列出目录的下所有文件和文件夹保存到lists
    print(list)
    lists.sort(key=lambda fn:os.path.getmtime(test_report + "\\" + fn))#按时间排序
    file_new = os.path.join(test_report,lists[-1])                     #获取最新的文件保存到file_new
    print(file_new)
    return file_new
if __name__=="__main__":
    test_report="path"#目录地址
    new_report(test_report)

df_data=dataPress(fileName)
# os.remove(u'./upload/{}'.format(fileName))


def get_filelist(dir, Filelist):
    try:
        lists = os.listdir(dir) 
        lists.sort(key=lambda fn:os.path.getmtime(dir + "\\" + fn))
        if len(lists)>1:
            lists=[i for i in lists if (R"xlsx" in i)]
            for i in lists:
                print(i)
                if i !=lists[-1] or R"xlsx" not in i :
                    os.remove(u'./upload/{}'.format(i))
        file_new = lists[-1]       
        print(file_new)
        if R"xlsx" in file_new:
            return file_new
        # for s in os.listdir(dir):
        #     if R"xlsx" in s:
        #         print(s)
        #         Filelist.append(s) 
        # return Filelist[0]
    except Exception,err:
        print(err)
        return Filelist

def dataPress(fileName):
    print("done >>>>>>>>>>",fileName.decode("utf-8"))
    try:
        excel_reader=pd.ExcelFile(u'./upload/{}'.format(fileName))
    except Exception,err:
        if R"xlsx" in str(err):
            df=pd.ExcelFile(u'./upload/{}'.format(fileName),engine='openpyxl')
    sheet_names = excel_reader.sheet_names
    lis=[]
    if R"dataflow" in sheet_names:
        df_data =  excel_reader.parse(sheet_name="dataflow")
        df_=df_data.iloc[1:5,1:5]
        df_.iloc[:,2:4] = np.nan
        for tup in df_.itertuples():
            lis.append(tup[1:])
            # print(tup[1:])
    print(lis)
    return lis
    # result = _common.mysql_select(sql, withcolumns=False)