2021牛客寒假算法基础集训营4，签到题AGJ

A. 九峰与签到题

#include
using namespace std;
typedef long long LL;
struct node{
     int ac=0, unac=0;}a[50];
int vis[50];
int main(){
     
	int m, n;  cin>>m>>n;
	for(int i = 1; i <= m; i++){
     
		int x; string op;  cin>>x>>op;
		if(op=="AC")a[x].ac++;else a[x].unac++;
		if(a[x].ac+a[x].unac==1 && a[x].unac==1)vis[x] = 1;
		if(a[x].ac*1.0/(a[x].ac+a[x].unac) < 0.5)vis[x] = 1;
	}
	vector<int>ans;
	for(int i = 1; i <= n; i++)
		if(vis[i]==0 && a[i].ac+a[i].unac!=0)ans.push_back(i);
	if(ans.size()==0)cout<<"-1";
	else{
     
		for(int i = 0; i < ans.size(); i++)
			cout<<ans[i]<<" ";
	}
	return 0;
}

G. 九峰与蛇形填数

#include
using namespace std;
typedef long long LL;
const int maxn = 4e3+10;
int a[maxn][maxn], x[maxn], y[maxn], k[maxn];
int main(){
     
	ios::sync_with_stdio(false);
	int n, m;  cin>>n>>m;
	int x1 = maxn, x2 = 1, y1 = maxn, y2 = 1;
	for(int i = 1; i <= m; i++){
     
		cin>>x[i]>>y[i]>>k[i];
		x1 = min(x1,x[i]);
		x2 = max(x2,x[i]+k[i]-1);
		y1 = min(y1,y[i]);
		y2 = max(y2,y[i]+k[i]-1);
	}
	for(int i = 1; i <= n; i++){
     
		for(int j = 1; j <= n; j++){
     
			for(int z = m; z >= 1; z--){
     
				if(i<x1||i>x2||j<y1||j>y2)break;
				if(i>=x[z] && i<=x[z]+k[z]-1 && j>=y[z]&&j<=y[z]+k[z]-1){
     
					a[i][j] = (i-x[z])*k[z];
					if((i-x[z])%2==1)a[i][j]+=y[z]+k[z]-1-j+1;
					else a[i][j]+=j-y[z]+1;
					break;
				}
			}
		}
	}
	for(int i = 1; i <= n; i++){
     
		for(int j = 1; j <= n; j++)
			cout<<a[i][j]<<" ";
		cout<<"\n";
	}
	return 0;
}

J. 邬澄瑶的公约数

#include
using namespace std;
typedef long long LL;
const int maxn = 1e4+10;
const int mod = 1e9+7;
int a[maxn], b[maxn];//,c[maxn];
bitset<maxn>p;
LL pows(LL a, LL b, LL m) {
     
	a %= m;
	LL res = 1;
	while(b>0){
     
		if(b&1)res=res*a%m;
		a = a*a%m;
		b >>= 1;
	}
	return res%m;
}
int main(){
     
	int n; cin>>n;
	int _max = 0;
	for(int i = 1; i <= n; i++){
     cin>>a[i]; _max = max(_max,a[i]);}
	for(int i = 1; i <= n; i++)cin>>b[i];
	
	LL ans = 1, c;
	for(int i = 2; i <= _max; i++){
     
		if(p[i])continue;
		for(int j = 2*i; j <= _max; j+=i){
     
			p[j] = 1;
		}
		c = mod;
		for(int j = 1; j <= n; j++){
     
			if(a[j]%i!=0){
     c = 0; break;}
			else{
     
				int t = a[j], tt = 0;
				while(t>0 && t%i==0){
     t/=i;tt++;}
				if(tt*b[j]!=1)c = min(c,(LL)tt*b[j]);
				else c = 1;
				//cout<
			}
		}
		//cout<
		if(c!=0 && c!=mod)ans = ans*pows(i,c,mod)%mod;
	}
	cout<<ans<<"\n";
	return 0;
}