Selenium 如在在 windows 窗口，上传文件 (代码仅针对 chrome 浏览器)

有2种情况：

file_path = "C:\Usersj\Documents\1111.txt"

1.如果标签名是input，可以直接输入路径，直接调用send_keys

driver.find_element(By.ID,'aa').send_keys(file_path)

2.非input标签的上传，则需要第三方工具

2.1 AutoIt

具体可以参考虫师的博客

; Wait 10 seconds for the Upload window to appear

WinWait("[CLASS:#32770]","",5)

; Set the File name text on the Edit field

controlSetText("打开","","Edit1","C:\Users\hongzj\Pictures\七夕\1.gif")

Sleep(2000)

; Click on the Open button

ControlClick("打开","","Button1");

2.2SendKeys第三方库（目前只支持到2.7版本）

2.3 Python pywin32库，识别对话框句柄，进而操作

import win32gui

import win32con

def upload_chrome(filepath):

# x一级窗口

dialog = win32gui.FindWindow("#32770","打开")

# 二级窗门

Comboboxex32 = win32gui.FindWindowEx(dialog, 0, 'Comboboxex32', None)

# 三级窗口

combobox = win32gui.FindWindowEx(Comboboxex32, 0, 'Combobox', None)

# 四级窗口-文件路经输入框

edit = win32gui.FindWindowEx(combobox, 0, 'Edit', None)

# 二级窗口一打开按钮

button = win32gui.FindWindowEx(dialog, 0, "Button", "打开(&0)")

# 操作一#发送文件路经

win32gui.SendMessage(edit, win32con.WM_SETTEXT, None, filepath)

# 点击打开按钮

win32gui.SendMessage(dialog, win32con.WM_COMMAND, 1, button)

指定要上传的文件路径

upload_chrome(file_path)