李飞JQuery之getJSON
最近用jQuery做了一个ajax验证，用到了json的
jQuery.getJSON(url, [data], [callback])
代码贴出来以便共享：
前台请求jsp页面testJson.jsp
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme() + "://" + request.getServerName() + ":" + request.getServerPort()
+ path + "/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>My JSP 'test11.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<script type="text/javascript" src="../js/jquery-1.4.min.js"></script>
<script type="text/javascript">
$(function(){
$.getJSON("testdata.jsp?username=lifei&[email protected]&callback=?",function(data){
alert("username: "+data.username+" email: "+data.email);
});
});
</script>
</head>
<body>
</body>
</html>
后台jsp页面testdata.jsp
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%
/**
*@auth:李飞
*@QQ1873922520
*/
response.setContentType("application/json");//这个一定要加
String callback = request.getParameter("callback");
String email = request.getParameter("email");
String username = request.getParameter("username");
String remsg = "{\"username\":\"" + username + "\",\"email\":\"" + email + "\"}";
%>
<%=callback + "(" + remsg + ")"%>