目录
resultmap 为对象赋值的调用顺序
java bean定义如下
部分mybatis映射文件如下
createResultObject方法的代码如下
使用resultMap时需注意的问题
直接用原始方式就行
如果是实体中是list集合
使用association 标签来写
应该使用collection标签
resultmap 为对象赋值的调用顺序
写了一个mybatis的mapper映射文件,
java bean定义如下
public class GroupCourseResult extends GroupResult {
private String cid;
private String cname;
public GroupCourseResult(int stuschool, int nian, String stuclass, String cid, String cname) {
super(stuschool, nian, stuclass);
this.cid = cid;
this.cname = cname;
}
public String getCid() {
return cid;
}
public void setCid(String cid) {
this.cid = cid;
}
public String getCname() {
return cname;
}
public void setCname(String cname) {
this.cname = cname;
}
}
部分mybatis映射文件如下
实体类中的属性名和查询的列名完全匹配,但是没有查询stuclass,则封装后的实体类中的stuclass属性应该为空。
然而程序运行后,stuclass属性不仅不为空,还与cname完全相同,百思不得其解,故翻了翻mybatis的源码。
在mybatis中的DefaultResultSetHandler类中,
createResultObject方法的代码如下
private Object createResultObject(ResultSetWrapper rsw, ResultMap resultMap, List> constructorArgTypes, List constructorArgs, String columnPrefix)
throws SQLException {
final Class> resultType = resultMap.getType();
final MetaClass metaType = MetaClass.forClass(resultType, reflectorFactory);
final List constructorMappings = resultMap.getConstructorResultMappings();
if (hasTypeHandlerForResultObject(rsw, resultType)) {
return createPrimitiveResultObject(rsw, resultMap, columnPrefix);
} else if (!constructorMappings.isEmpty()) {
return createParameterizedResultObject(rsw, resultType, constructorMappings, constructorArgTypes, constructorArgs, columnPrefix);
} else if (resultType.isInterface() || metaType.hasDefaultConstructor()) {
return objectFactory.create(resultType);
} else if (shouldApplyAutomaticMappings(resultMap, false)) {
return createByConstructorSignature(rsw, resultType, constructorArgTypes, constructorArgs);
}
throw new ExecutorException("Do not know how to create an instance of " + resultType);
}
经过调试发现,mybatis会先查找该javabean有无默认构造方法,如果有则采用设值注入,若没有,则根据javabean的有参构造方法进行设值,而在8以前的jdk版本中,我们利用反射只能获取到参数类型,不能获取到参数名称,这其中设值可能出现了匹配失误,将cname的值同时赋给了cname和stuclass。
想要解决这个问题,只须在javabean中添加默认构造方法即可。
使用resultMap时需注意的问题
如果是实体中是直接引用别的对象的具体参数字段,
直接用原始方式就行
SELECT
eer.visit_number as visitNumber,
eer.patient_name as patientName,
eer.send_time as sendTime,
eek.id as id,
eek.ward_code as wardCode,
eek.ward_name as wardName,
eek.category_code as categoryCode,
eek.title as title,
eek.content as content,
eek.cover as cover
FROM
edu_education_record AS eer,
edu_education_knowledge AS eek
WHERE
eer.education_knowledge_id=eek.id
如果是实体中是list集合
SELECT
eer.visit_number as visitNumber,
eer.patient_name as patientName,
eer.send_time as sendTime,
eek.id as id,
eek.ward_code as wardCode,
eek.ward_name as wardName,
eek.category_code as categoryCode,
eek.title as title,
eek.content as content,
eek.cover as cover
FROM
edu_education_record AS eer,
edu_education_knowledge AS eek
WHERE
eer.education_knowledge_id=eek.id
如果实体中引用的是别的对象,
使用association 标签来写
SELECT
eer.visit_number as visitNumber,
eer.patient_name as patientName,
eer.send_time as sendTime,
eek.id as id,
eek.ward_code as wardCode,
eek.ward_name as wardName,
eek.category_code as categoryCode,
eek.title as title,
eek.content as content,
eek.cover as cover
FROM
edu_education_record AS eer,
edu_education_knowledge AS eek
WHERE
eer.education_knowledge_id=eek.id
如果实体中是引用的别的对象的list集合,
应该使用collection标签
SELECT
eer.visit_number as visitNumber,
eer.patient_name as patientName,
eer.send_time as sendTime,
eek.id as id,
eek.ward_code as wardCode,
eek.ward_name as wardName,
eek.category_code as categoryCode,
eek.title as title,
eek.content as content,
eek.cover as cover
FROM
edu_education_record AS eer,
edu_education_knowledge AS eek
WHERE
eer.education_knowledge_id=eek.id
tips:
使用resultMap的时候,应该直接用as后面的字段名,即自己命的名字
如果没有使用as的话,直接使用数据库中原本的名字
resultMap中各个标签的含义
tips:
在一个 resultMap 元素中,这些子元素出现的先后顺序是有严格规定的,它们从前到后依次是:constructor–>id --> result–> association–>collection -->discriminator, 不然就会报错。
以上为个人经验,希望能给大家一个参考,也希望大家多多支持脚本之家。