不更改链表结构,只是添加节点,没有删除节点。通过记录和更改标记来模拟题意的插入和删除,复制
指针模拟链表:
预开指针,存在M[]中,可以提高效率
#include<functional> #include<algorithm> #include<iostream> #include<cstring> #include<cstdio> #include<vector> #include<cmath> #include<string> #include<queue> #include<map> #include<set> #include <stack> #define REP(i, n) for(int i=0; i<n; i++) #define PB push_back #define LL long long #define CLR(a, b) memset(a, b, sizeof(a)) using namespace std; const int maxn = 500005; struct point{ int val; point *pre; }M[maxn * 2]; int tot; struct node{ point *a, *b; }c[maxn]; void add(point* &pre, int y) { point *u = &M[tot++]; u->val = y; u->pre = pre; pre = u; } void del(point* &last) { last = last->pre; } int t, m, n; int main() { char op[12]; tot = 1; n = 1; int x, y; scanf("%d%d", &t, &m); while (t--) { scanf("%s", op); scanf("%d", &x); if (op[0] == 'l') { scanf("%d", &y); add(c[x].a, y); c[x].b = NULL; } else if (op[0] == 'r' && op[1] == 'o') { if (c[x].a) { add(c[x].b, c[x].a->val); del(c[x].a); } } else if (op[0] == 'r' && op[1] == 'e') { if (c[x].b) { add(c[x].a, c[x].b->val); del(c[x].b); } } else if (op[0] == 'c' && op[1] == 'l') { c[++n] = c[x]; } else { if (!c[x].a) printf("basic\n"); else printf("%d\n", c[x].a->val); } } }
数组模拟链表:
#include<functional> #include<algorithm> #include<iostream> #include<cstring> #include<cstdio> #include<vector> #include<cmath> #include<string> #include<queue> #include<map> #include<set> #include <stack> #define REP(i, n) for(int i=0; i<n; i++) #define PB push_back #define LL long long #define CLR(a, b) memset(a, b, sizeof(a)) using namespace std; const int maxn = 500005; struct point{ int val; int pre; }P[maxn * 2]; struct node{ int a, b; node(){} node(int a, int b) : a(a), b(b){} }c[maxn]; int tot; int t, m, n; void add(int u, int &pre, int y) { P[tot].pre = pre; P[tot].val = y; pre = tot++; } void del(int &last) { last = P[last].pre; } int main() { char op[12]; n = 1; tot = 1; int x, y; scanf("%d%d", &t, &m); while (t--) { scanf("%s", op); scanf("%d", &x); if (op[0] == 'l') { scanf("%d", &y); add(x, c[x].a, y); c[x].b = 0; } else if (op[0] == 'r' && op[1] == 'o') { if (c[x].a) { add(x, c[x].b, P[c[x].a].val); del(c[x].a); } } else if (op[0] == 'r' && op[1] == 'e') { if (c[x].b) { add(x, c[x].a, P[c[x].b].val); del(c[x].b); } } else if (op[0] == 'c' && op[1] == 'l') { c[++n] = node(c[x].a, c[x].b); } else { if (!c[x].a) printf("basic\n"); else printf("%d\n", P[c[x].a].val); } } }