数学趣题——三重回文数字

找出11——999之间的所有三重回文数字，就是a的a,a平方，a立方都是回文

   1: #include "stdio.h"

   2:  

   3: long reverse(long i)

   4: {   /*求i 的倒置数*/

   5:     long m, j = 0;

   6:     m = i;

   7:  

   8:     while(m) {

   9:         j = j * 10 + m % 10;

  10:         m = m / 10;

  11:     }

  12:  

  13:     return j;   /*返回i的倒置数j*/

  14: }

  15:  

  16: long isCircle(long n)

  17: {   /*函数isCircle 判断n是否是回文数字*/

  18:     long m;

  19:     m = reverse(n);

  20:  

  21:     if(m == n)

  22:         return 1;

  23:     else

  24:         return 0;

  25: }

  26:  

  27: void palindrome(long low, long high)

  28: {

  29:     long i;

  30:  

  31:     for(i = low; i <= high; i++)

  32:     {

  33:         if(isCircle(i) && isCircle(i * i) && isCircle(i * i * i))

  34:             printf("%d ", i);

  35:     }

  36: }

  37:  

  38: int main()

  39: {

  40:     printf("The palindrome numbers between 11~999 are\n");

  41:     palindrome(11, 999);

  42:     return 0;

  43: }