zjfc----1076 online judge 对多行字符串输入做处理

题目描述

Ignatius is building an Online Judge, now he has worked out all the problems except the Judge System. The system has to read data from correct output file and user's result file, then the system compare the two files. If the two files are absolutly same, then the Judge System return "Accepted", else if the only differences between the two files are spaces(' '), tabs('\t'), or enters('\n'), the Judge System should return "Presentation Error", else the system will return "Wrong Answer".

Given the data of correct output file and the data of user's result file, your task is to determine which result the Judge System will return.

输入描述

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.

Each test case has two parts, the data of correct output file and the data of the user's result file. Both of them are starts with a single line contains a string "START" and end with a single line contains a string "END", these two strings are not the data. In other words, the data is between the two strings. The data will at most 5000 characters.

输出描述

For each test cases, you should output the the result Judge System should return.

样例输入

4

START

1 + 2 = 3

END

START

1+2=3

END

START

1 + 2 = 3

END

START

1 + 2 = 3

END

START

1 + 2 = 3

END

START

1 + 2 = 4

END

START

1 + 2 = 3

END

START

1	+	2	=	3

END

样例输出

Presentation Error

Presentation Error

Wrong Answer

Presentation Error

   
     

    
      
    
      
    
      Code
    
      
 
       #include<stdio.h>
 #include<string.h>
 char a[5005],b[5005],tmp[5005];
 int t;
 void input(char *str)
 {
     getchar();
     gets(tmp);
     str[0]='\0';
     while(gets(tmp)&&strcmp(tmp,"END")){
         if(strlen(tmp)==0)
             strcat(str,"\n");
         else
             strcat(str,tmp);
     }
 }
 void mdo(char *s)
 {
     int i,j;
     int len=strlen(s);
     for(i=0,j=0;i<len;i++){
         if(s[i]==' '||s[i]=='\t'||s[i]=='\n')
             continue;
         tmp[j++]=s[i];
     }
     tmp[j]='\0';
     strcpy(s,tmp);
 }
 int process()
 {
     mdo(a);mdo(b);
     if(strcmp(a,b)==0)
         return 1;
     return 0;
 }
 int main()
 {
     scanf("%d",&t);
     while(t--){
         input(a);
         input(b);
         if(strcmp(a,b)==0)
             printf("Accepted\n");
         else if(process())
             printf("Presentation Error\n");
         else
             printf("Wrong Answer\n");
     }
 }