poj1563

简单题

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//zoj1710

//当蜗牛每天白天爬升的距离因疲劳值过多而减为负数时，认为爬升距离为0，不认为下降。

#include <iostream>

#include <cmath>

using namespace std;



int        h, u, d, f,time1;

double    now, speed;



void work()

{

    while (1)

    {

        now += speed;

        if (now > h)

        {

            cout << "success on day " << time1 << endl;

            break;

        }

        now -= d;

        if (now < 0)

        {

            cout << "failure on day " << time1 << endl;

            break;

        }

        time1++;

        speed -= u * f / 100.0;

        if (speed < 0)

            speed = 0;

    }

}



int main()

{

//    freopen("t.txt", "r", stdin);

    while (cin >> h >> u >> d >> f && h != 0)

    {

        now = 0;

        time1 = 1;

        speed = u;

        work();

    }

    return 0;

}