继续应用回溯法解决迷宫问题:
问题赘述一下,从一点出发找到出口即可
package 数据结构及算法.回溯法应用之迷宫问题;
import java.util.Iterator;
import 数据结构及算法.回溯法.Application;
import 数据结构及算法.回溯法.Position;
public class Maze implements Application{
private static final byte WALL=0;
private static final byte CORRIDOR=1;//非墙,走廊
private static final byte PATH=9;
private static final byte TRIED=2;
private Position finish;
private byte[][] grid;
public Maze(byte[][]grid,Position finish){
this.finish=finish;
this.grid=grid;
}
@Override
public boolean valid(Position pos) {
if(pos.getRow()>=0&&
pos.getRow()<this.grid.length&&
pos.getColumn()>=0&&
pos.getColumn()<this.grid[0].length&&
grid[pos.getRow()][pos.getColumn()]==this.CORRIDOR){
return true;
}
return false;
}
@Override
public void record(Position pos) {
grid[pos.getRow()][pos.getColumn()]=this.PATH;
}
@Override
public boolean done(Position pos) {
return this.finish.getRow()==pos.getRow()&&this.finish.getColumn()==pos.getColumn();
}
@Override
public void undo(Position pos) {
this.grid[pos.getRow()][pos.getColumn()]=this.TRIED;
}
public String toString(){
String result="";
for(int i=0;i<this.grid.length;i++){
for(int j=0;j<this.grid[0].length;j++){
result+=this.grid[i][j]+" ";
}
result+="\n";
}
return result;
}
@SuppressWarnings("rawtypes")
@Override
public Iterator iterator(Position pos) {
return new MazeIterator(pos);
}
@SuppressWarnings("rawtypes")
private class MazeIterator implements Iterator{
private int row=0;
private int column=0;
private int count=0;
public MazeIterator(Position pos) {
this.row=pos.getRow();
this.column=pos.getColumn();
}
@Override
public boolean hasNext() {
return this.count<4;
}
@Override
public Object next() {
Position nextPosition=new Position();
switch(count){
case 0:nextPosition=new Position(row-1,column);
break;//north
case 1:nextPosition=new Position(row,column+1);
break;//east
case 2:nextPosition=new Position(row+1,column);
break;//south
case 3:nextPosition=new Position(row,column-1);
break;//west
}
count++;
return nextPosition;
}
@Override
public void remove() {
throw new UnsupportedOperationException();
}
}
}
初始情况是输入的整个矩阵,1表示可走的,0表示墙
public boolean valid(Position pos)中判断为在矩阵内切非墙有效
在public void record(Position pos)中我让该位置记为9.表示走过
public void undo(Position pos),撤销时与上是逆过程;记为2,
private class QueenIterator implements Iterator为内部类,记录某位置的下一行可选位置,按照北,东,南,西的顺序找
测试程序如下
package 数据结构及算法.回溯法应用之迷宫问题;
import java.util.Scanner;
import 数据结构及算法.回溯法.Application;
import 数据结构及算法.回溯法.BackTrack;
import 数据结构及算法.回溯法.Position;
public class MazeTest {
private byte[][]grid;
public MazeTest(byte[][]grid){
Scanner sc=new Scanner(System.in);
String prompt="请输入四个数字,分别作为迷宫的起始点与终点的row,column坐标!";
System.out.println(prompt);
String s=sc.nextLine();
this.grid=grid;
pocessInput(s);
}
public void pocessInput(String s) {
String[] ss=s.split(" ");
int startR=Integer.parseInt(ss[0]);
int startC=Integer.parseInt(ss[1]);
int finalR=Integer.parseInt(ss[2]);
int finalC=Integer.parseInt(ss[3]);
Position startPosition=new Position(startR,startC);
Position finalPosition=new Position(finalR,finalC);
Application app=new Maze(grid, finalPosition);
BackTrack backTrack=new BackTrack(app);
println("开始为:");
println(app.toString());
if(!app.valid(startPosition)||!app.valid(finalPosition)){
println("failure!");
}
else{
app.record(startPosition);
if(app.done(startPosition)||backTrack.tryToSolve(startPosition)){
println("success");
}
else{
app.undo(startPosition);
println("failure!");
}
}
println("最终为:");
println(app.toString());
}
public void println(String s){
System.out.println(s);
}
public static void main(String[]args){
byte[][] grid={{1,1,1,0,1,1,0,0,0,1,1,1,1},
{1,0,1,1,1,1,0,1,1,1,1,1,0},
{1,0,0,0,1,0,1,0,1,0,1,0,1},
{1,0,0,0,1,1,1,0,1,0,1,1,1},
{1,1,1,1,1,0,0,0,0,1,0,0,0},
{0,0,0,0,1,0,0,0,0,0,0,0,0},
{0,0,0,0,1,1,1,1,1,1,1,1,1}
};
new MazeTest(grid);//测试用例 0 0 6 12
}
}
终于把写的东西弄上来了,希望对和我一样的菜鸟有帮助