【python代码】解析labelme的json文件转换为yolo标签格式

import json
import os

def convert(img_size, box):
    # dw = 1. / (img_size[0])
    # dh = 1. / (img_size[1])
    # x = (box[0] + box[2]) / 2.0 - 1
    # y = (box[1] + box[3]) / 2.0 - 1
    # w = box[2] - box[0]
    # h = box[3] - box[1]
    # x = x * dw
    # w = w * dw
    # y = y * dh
    # h = h * dh
    x1 = box[0]
    y1 = box[1]
    x2 = box[2]
    y2 = box[3]
    return (x1, y1, x2, y2)


def decode_json(json_floder_path, json_name):
    txt_name = 'E:/W3/txt/' + json_name[0:-5] + '.txt'
    txt_file = open(txt_name, 'w')

    json_path = os.path.join(json_floder_path, json_name)
    data = json.load(open(json_path, 'r', encoding='utf-8'))

    img_w = data['imageWidth']
    img_h = data['imageHeight']

    for i in data['shapes']:

        if (i['shape_type'] == 'rectangle' and i['label'] == '0'):
            x1 = int(i['points'][0][0])
            y1 = int(i['points'][0][1])
            x2 = int(i['points'][1][0])
            y2 = int(i['points'][1][1])

            bb = (x1, y1, x2, y2)
            bbox = convert((img_w, img_h), bb)
            txt_file.write( '0' + " " + " ".join([str(a) for a in bbox]) + '\n')


if __name__ == "__main__":

    json_floder_path = 'E:/W3/json'
    json_names = os.listdir(json_floder_path)
    for json_name in json_names:
        decode_json(json_floder_path, json_name)

源代码来自该博主,嘻嘻:)