字符串转十六进制ascii c语言程序,Hex到ascii字符串转换

您需要同时使用2(十六进制)字符…然后计算int值

之后,使char转换像…

char d =(char)intValue;

对于十六进制字符串中的每个2chars来执行此操作

如果字符串字符只有0-9A-F,则这样做：

#include

#include

int hex_to_int(char c){

int first = c / 16 - 3;

int second = c % 16;

int result = first*10 + second;

if(result > 9) result--;

return result;

}

int hex_to_ascii(char c,char d){

int high = hex_to_int(c) * 16;

int low = hex_to_int(d);

return high+low;

}

int main(){

const char* st = "48656C6C6F3B";

int length = strlen(st);

int i;

char buf = 0;

for(i = 0; i < length; i++){

if(i % 2 != 0){

printf("%c",hex_to_ascii(buf,st[i]));

}else{

buf = st[i];

}

}

}