the least common multiplier

Description

There are many unsolvable problem in the world.It could be about one or about zero.But this time it is about bigger number. 
Given an integer n(2 <= n <= 10  ⁹).We should find a pair of  positive integer a, b so that a + b = n and [a, b] is as large as possible. [a, b] denote the least common multiplier of a, b.

 

Input

The first line contains integer T(1<= T<= 10000),denote the number of the test cases. 
For each test cases,the first line contains an integer n.

 

Output

For each test cases,  print the maximum [a,b] in a line.

 

Sample Input

3 2 3 4

 

Sample Output

1 2 3

 

#include <iostream>

using namespace std;

int gcd(int a,int b){

    int c=b%a;

    while(c>0){

        b=a;

        a=c;

        c=b%a;

    }

return a;

}



int main()

{

    int t;cin>>t;int n;

    while(t--){

        __int64 sum=0,i;

        cin>>n;

        for(i=n/2;i>0;i--){

            if(gcd(i,n-i)==1)

            {

                sum=i*(n-i);

                break;

            }

        }

        cout<<sum<<endl;

    }

 return 0;

}

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