python判断电话号码是否合理_python 判断号码是否可用(号码过滤)

def delCustomer(customer): # 返回两个 第一个用来标记是否可用，第二个标记号码

f = open(AbnormalPhone,"r")

src = f.readlines()

f.close()

abnormalSet = set()

for line in src:

phone = str(line.split("\n")[0].strip())

abnormalSet.add(phone)

matchObj = re.match('0?1[3-9]\d{9}$', customer)

if (matchObj!=None): # 如果是手机号

if len(customer) == 11:

return 1,customer

elif len(customer) == 12:

return 1,customer[1:]

else: #如果不是手机号

matchObj = re.match('0(10|2\d)', customer) # 区号是3位 customer[0:3], customer[3:] 区号，号码

if (matchObj != None):

if (len(customer[3:]) == 7 or len(customer[3:]) == 8) and customer not in abnormalSet:

return 1,customer

else:

return 0,customer

matchObj = re.match('0([3-9]\d{2})', customer) # 区号是4位 customer[0:4], customer[4:] 区号，号码

if (matchObj != None):

if (len(customer[4:]) == 7 or len(customer[4:]) == 8) and customer not in abnormalSet:

return 1,customer

else:

return 0, customer

if (len(customer) == 7 or len(customer) == 8) and customer not in abnormalSet:

return 1,customer

else:

return 0,customer