参考:https://www.runoob.com/w3cnote/python-understanding-dict-copy-shallow-or-deep.html
- 赋值:变量直接指向对象
ls = [i for i in range(0,10)] # [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
lss = ls # [10, 10, 10, 10, 10, 10, 10, 10, 10, 10]
for idx,v in enumerate(lss):
lss[idx] = 10
lss # [10, 10, 10, 10, 10, 10, 10, 10, 10, 10]
ls # [10, 10, 10, 10, 10, 10, 10, 10, 10, 10]
- 浅拷贝:只拷贝父对象,不会拷贝对象中的子对象(而是引用地址)
ls = [[0,0,0], 1, 2, 3, 4, 5, 6, 7, 8, 9]
lss = ls.copy() # [[0,0,0], 1, 2, 3, 4, 5, 6, 7, 8, 9]
for idx in range(1,len(ls)):
lss[idx] = 10
lss[0].append(99)
ls # [[0, 0, 0], 1, 2, 3, 4, 5, 6, 7, 8, 9]
lss # [[0, 0, 0, 99], 10, 10, 10, 10, 10, 10, 10, 10, 10]
需要注意的是,
ls = [[0,0,0], 1, 2, 3, 4, 5, 6, 7, 8, 9]
lss = ls.copy() # [10, 10, 10, 10, 10, 10, 10, 10, 10, 10]
for idx in range(1,len(ls)):
lss[idx] = 10
# 这里又做了一次浅拷贝,所以不会影响值
for i in lss[0]:
i = 99
ls # [[0, 0, 0], 1, 2, 3, 4, 5, 6, 7, 8, 9]
lss # [[0, 0, 0], 10, 10, 10, 10, 10, 10, 10, 10, 10]
- 深拷贝:完全拷贝,不会对原变量产生影响
ls = [[0,0,0], 1, 2, 3, 4, 5, 6, 7, 8, 9]
lss = ls.copy() # [[0,0,0], 1, 2, 3, 4, 5, 6, 7, 8, 9]
for idx in range(1,len(ls)):
lss[idx] = 10
lss[0].append(99)
ls # [[0, 0, 0], 1, 2, 3, 4, 5, 6, 7, 8, 9]
lss # [[0, 0, 0, 99], 10, 10, 10, 10, 10, 10, 10, 10, 10]