async 方法异常重新执行的方法

async 方法异常重新执行的方法

let asyncFunc = async () => {
    let i = 0;
    while (true) {
        let value = await new Promise((resolve, reject) => {
            if (i > 10) {
                aa();
            }
            setTimeout(() => {
                i++;
                resolve(i);
            }, 1000)
        });
        console.log(value)
    }


};

let run = () => {
    asyncFunc().then(resp => {
        console.log(resp);
    }).catch(e => {
        console.log(e)
        run();
    })
};
run();