程序设计练习题

算法竞赛入门经典

习题1-1平均数

#include
int main() {

    int a, b, c, sum;
    float average;
    scanf("%d%d%d", &a, &b, &c);
    sum = a + b + c;
    average = sum / 3;
    printf("%.3f \n", average);

    return 0;

}

习题1-2温度

#pragma warning(disable:4996)
#include
int main() {

    float f, c;
    scanf("%f", &f);
    c = 5 * (f - 32) / 9;
    printf("%.3f", c);

}

习题1-3

#pragma warning(disable:4996)
#include
int main() {

    int n, sum;
    scanf("%d", &n);
    sum = (1 + n) * n / 2;
    printf("%d", sum);

}

习题1-4

#include
#include
#define PI 3.14159265
int main() {

    double n, sinn = 0, cosn = 0;
    double m, val;
    //printf("%f", n);
    scanf("%lf", &n);
    val = PI / 180;
    sinn = sin(n * val);
    cosn = cos(n * val);
    printf("%.3f %.3f\n", sinn, cosn);
    return 0;
}

习题1-5

#include

int main() {

    int price = 95, n = 0;
    double sum;
    scanf("%d", &n);
    sum = n * price;
    if (sum >= 300) {
        sum = sum * 0.85;
        printf("%.2f", sum);
    }

    return 0;
}

习题1-6

#pragma warning(disable:4996)
#include

int main() {

    int a, b, c;
    int a2, b2, c2;

    scanf("%d%d%d", &a, &b, &c);
    a2 = a * a;
    b2 = b * b;
    c2 = c * c;
    if ((a + b > c) && (a + c > b) && (b + c > a)) {
        if ((a2 + b2 == c2) || (a2 + c2 == b2) || (b2 + c2 == a2)) {
            printf("yes");
        }
        else {
            printf("no");
        }
    }
    else {
        printf("not a triangle");
    }

}

习题1-7

#pragma warning(disable:4996)
#include

int main() {

    int year;
    scanf("%d", &year);
    if ((year % 4 == 0 && year % 100 != 0) ||(year % 400 == 0)) {
        printf("yes");

    
    
    }
    else {
        printf("no");
    }

}

习题2-1水仙花数

#pragma warning(disable:4996)
#include
int main() {
    int i = 100;
    for (i = 100; i <= 999; i++) {
        int a = 0, b = 0, c = 0;
        a = i % 10;
        b = (i /10)% 10;
        c = i /100;
        if ((a * a*a  + b * b*b + c * c *c== i)) {
            printf("%d\n", i);
        }
    }
}

习题2-2韩信点兵

#pragma warning(disable:4996)
#include
int main() {
    int i = 10;

    int a, b, c, kase = 0;
    while (scanf("%d%d%d", &a, &b, &c) == 3) {
        kase =kase+1;
        int m = -1;
        for (i = 10; i <= 100; i++) {
            if (i % 3 == a && i % 5 == b && i % 7 == c) {
                m = i;
                break;
            }
        }
        if (m != -1) {
                printf("case %d: %d\n", kase, m);
            }
            else {
                printf("case %d: No answer\n",kase);
            }
    }
}

习题2-3倒三角形

#pragma warning(disable:4996)
#include
int main() {
    int n = 0;
    scanf("%d", &n);
    for (int i = n; i > 0; i--) {//按行输入
    
            for (int j = n - i; j > 0; j--) {//输出空格
                printf(" ");
            }
            for (int j = 0; j < 2 * i - 1; j++) {
                printf("#");//输出#
            }
            printf("\n");//换行
        }
    
}

习题2-4子序列的和

#pragma warning(disable:4996)
#include
int main() {
    int kase = 0;
    int n=1,m;
    while (scanf("%d%d", &n, &m) == 2 && n != 0) {
        kase += 1;
        double num = 0;
        for (long long  i = n; i <=m; i++) {
            num += 1.0 / (i * i);
        }
        printf("Case %d: %.5f", kase, num);
    
    }
}

习题2-5分数化小数

#pragma warning(disable:4996)
#include
int main() {
    int kase = 0;
    int a, b, c;
    double num = 0;
    while (scanf("%d%d%d", &a, &b, &c ) == 3 && a != 0) {
        kase += 1;
        num = (a*1.0) / b;
        printf("Case %d: %.*f", kase,c,num );
//
    
    }
    return 0;
}

习题2-6排列

#pragma warning(disable:4996)

#include
#include
#include
using namespace std;
int main() { 
    int a, b, c;
    for (int i = 123; i < 329; i++) {
        set  s;//使用set中元素不可重复这一性质
        int a1 , a2 , a3 ,b1 , b2 , b3, c1 , c2 , c3 ;
        a = i;
        b = i * 2;
        c = i * 3;
        a1 = a % 10;
        a2 = a / 10 % 10;
        a3 = a / 100;
        b1 = b % 10;
        b2 = b / 10 % 10;
        b3 = b /100;
        c1 = c % 10;
        c2 = c / 10 % 10;
        c3 = c / 100;
        s.insert(a1);
        s.insert(a2);
        s.insert(a3);
        s.insert(b1);
        s.insert(b2);
        s.insert(b3);
        s.insert(c1);
        s.insert(c2);
        s.insert(c3);
        
        if ((b<=987&&c<=987)&&s.size()==9&&s.count(0)==0) {//需要判断是否存在0
            printf("%d %d %d\n", a, b, c);
        }
}
    return 0;
}

例3-3蛇形填数

#include
#include
#include
#define max 250
int a[max][max];

 int main(){
     int n, x, y;
     int  tot = 0;
     scanf("%d", &n);
     memset(a, 0, sizeof(a));
     tot = a[x = 0][y = n - 1] = 1;//使得第一个元素为1;

     
     while (tot < n * n) {
         while (x + 1 < n && !a[x + 1][y]) {
             x = x + 1;//x递增1
             tot = tot + 1;
             a[x][y] = tot;
         }
         while (y - 1 >= 0 && !a[x][y - 1]) {
             y = y - 1;
             tot = tot + 1;
             a[x][y] = tot;

         }
         while (x - 1 >= 0 && !a[x - 1][y]) {
             x = x - 1;
             tot = tot + 1;
             a[x][y] = tot;

         }
         while (y + 1 < n && !a[x][y + 1])
         {
             y = y + 1;
             tot = tot + 1;
             a[x][y] = tot;
         }
     }
     for (x = 0; x < n; x++) {
         for (y = 0; y < n; y++) {
             printf("%3d", a[x][y]);
             
         }
         printf("\n");
     }
     return 0;
}

循环单词

#pragma warning(disable:4996)
#include 
#include 
#include
#include
#include
#include
using namespace std;
#define max 100
int  getAnswer(string s1,string s2){
    for (int i = 0; i< s1.size(); i++) {
        for (int j = 0; j< s2.size(); j++) {
            if (s1[i] == s2[j] && j == s2.size() - 1) {
                return 1;
            }
            else {
                continue;
            }
        }
    }
    return 0;
}
int main()
{
    int a;
    cin >> a;
        int flag[max] = { 0 };
        char  s[10][30];
        for (int i = 0; i < a; i++) {
            scanf("%s", s[i]);
        }
        int count = 0;
        for (int j = 0; j < a; j++) {
            for (int m = j + 1; m < a; m++) {
                if (strlen(s[j]) != strlen(s[m])) {
                    break;
                }
                else {
                    string s1;
                    string s2;
                    string s3;
                    s1 = s[j];
                    s2 = s[m];
                    s3 = s1 + s1;
                    int f;
                    f = getAnswer(s3, s1);
                    if (flag[j]==0) {
                        count += f;
                    }
//这两行用去去重,确定共有几个单词模块
                    flag[m] = f;
                    flag[j] = f;
                }
            }
        }
        cout << count << endl;
    return 0;
}




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