Kotlin Flow 二 Flow 被压 backpressure

Kotlin 中的背压有如下三种方式。通过 buffer 操作符来完成。

buffer 操作指的是设置缓冲区。当然缓冲区有大小,如果溢出了会有不同的处理策略。

  1. 设置缓冲区,如果溢出了,则将当前协程挂起,直到有消费了缓冲区中的数据。
  2. 设置缓冲区,如果溢出了,丢弃最新的数据。
  3. 设置缓冲区,如果溢出了,丢弃最老的数据。

缓冲区的大小可以设置为 0,也就是不需要缓冲区。

设置缓冲区,并采用挂起的策略

suspend fun flowBackpressureBuffer(overflow: BufferOverflow) {
    fun currTime() = System.currentTimeMillis()
    var start: Long = 0
    val time = measureTimeMillis {
        (1..5).asFlow()
            .onStart { start = currTime() }
            .onEach {
                delay(100)
                println("Emit $it (${currTime() - start}ms)")
            }
            .buffer(capacity = 2, overflow)
            .collect {
                println("Collect $it starts (${currTime() - start}ms) ")
                delay(500)
                println("Collect $it ends (${currTime() - start}ms) ")
            }
    }
    println("Cost $time ms")
}

上述代码如果采用 BufferOverflow.SUSPEND 策略,也就是挂起策略。输入如下:

Emit 1 (111ms)
Collect 1 starts (113ms) 
Emit 2 (216ms)
Emit 3 (319ms)
Emit 4 (424ms)
Collect 1 ends (613ms) 
Collect 2 starts (614ms) 
Emit 5 (717ms)
Collect 2 ends (1117ms) 
Collect 3 starts (1118ms) 
Collect 3 ends (1620ms) 
Collect 4 starts (1621ms) 
Collect 4 ends (2125ms) 
Collect 5 starts (2125ms) 
Collect 5 ends (2630ms) 
Cost 2765 ms

可以看到第 4 发现缓冲区满了,所以就挂起了,当消费第 2 个的时候,此时 3 和 4 存储在了缓冲区内,此时发射第五个。因为 buffer 的容量是从 0 开始计算的。

设置缓冲区,丢弃最新的数据

如果上述代码传入 BufferOverflow.DROP_LATEST,输出如下:

Emit 1 (107ms)
Collect 1 starts (110ms) 
Emit 2 (213ms)
Emit 3 (314ms)
Emit 4 (419ms)
Emit 5 (524ms)
Collect 1 ends (613ms) 
Collect 2 starts (613ms) 
Collect 2 ends (1117ms) 
Collect 3 starts (1117ms) 
Collect 3 ends (1620ms) 
Cost 1728 ms

可以看到虽然发射了五个,但是丢弃了后面的两个数据。

设置缓冲区,丢弃旧数据

如果上述代码传入 BufferOverflow.DROP_OLDEST,输出如下:

Emit 1 (109ms)
Collect 1 starts (111ms) 
Emit 2 (214ms)
Emit 3 (317ms)
Emit 4 (419ms)
Emit 5 (525ms)
Collect 1 ends (613ms) 
Collect 4 starts (613ms) 
Collect 4 ends (1116ms) 
Collect 5 starts (1116ms) 
Collect 5 ends (1618ms) 
Cost 1716 ms

可以看到虽然发射了五个,但是 2,3 被丢弃了。

还有一个 conflate

confilate 操作符的作用不设缓冲区,丢弃旧数据。

suspend fun flowBackpressureLatest() {
    fun curTime() = System.currentTimeMillis()
    var start: Long = 0
    val time = measureTimeMillis {
        (1..5).asFlow()
            .onStart { start = curTime() }
            .onEach {
                delay(100)
                println("Emit $it (${curTime() - start}ms)")
            }
            .conflate()
            .collect {
                println("Collect $it start (${curTime() - start}ms) ")
                delay(500)
                println("Collect $it ends ${curTime() - start}ms) ")
            }
    }
    println("Cost $time")
}

输出如下:

Emit 1 (109ms)
Collect 1 start (111ms) 
Emit 2 (214ms)
Emit 3 (317ms)
Emit 4 (420ms)
Emit 5 (520ms)
Collect 1 ends 615ms) 
Collect 5 start (615ms) 
Collect 5 ends 1120ms) 
Cost 1226

conflate 操作符是不设缓冲区,也就是缓冲区大小为 0,丢弃旧数据,也就是采取 DROP_OLDEST 策略,那么不就等于 buffer(0, BufferOverflow.DROP_OLDEST)

我们来看看源码:

public fun  Flow.conflate(): Flow = buffer(CONFLATED)

public fun  Flow.buffer(capacity: Int = BUFFERED, onBufferOverflow: BufferOverflow = BufferOverflow.SUSPEND): Flow {
    require(capacity >= 0 || capacity == BUFFERED || capacity == CONFLATED) {
        "Buffer size should be non-negative, BUFFERED, or CONFLATED, but was $capacity"
    }
    require(capacity != CONFLATED || onBufferOverflow == BufferOverflow.SUSPEND) {
        "CONFLATED capacity cannot be used with non-default onBufferOverflow"
    }
    // desugar CONFLATED capacity to (0, DROP_OLDEST)
    var capacity = capacity
    var onBufferOverflow = onBufferOverflow
    **if (capacity == CONFLATED) {
        capacity = 0
        onBufferOverflow = BufferOverflow.DROP_OLDEST
    }**
    // create a flow
    return when (this) {
        is FusibleFlow -> fuse(capacity = capacity, onBufferOverflow = onBufferOverflow)
        else -> ChannelFlowOperatorImpl(this, capacity = capacity, onBufferOverflow = onBufferOverflow)
    }
}

所以 conflatebuffer(0, BufferOverflow.DROP_OLDEST) 的一种快捷方式。

下一篇 StateFlowSharedFlow 敬请期待。

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