I've been looking for help on how to find objects in Generics with List.Find() method .... and ... take a look what I have found.
In the follow example, I created a simple class:
public class Person
{
private int _id;
private string _name;
public int ID { get { return _id;} set { _id = value;}}
public int Name { get { return _name;} set { _name = value;}}
public Person( int id, string name)
{
_id = id;
_name = name;
}
}
In the example, there's a simple class with two private attributes. Now we're going to create a typed List of this object and take advantage of the Find() method
public void CreateAndSearchList()
{
// create and fill the collection
List < Person > myList = new List < Person > ();
myList.Add( new Person( 1 , " AndreySanches " ));
myList.Add( new Person( 2 , " AlexandreTarifa " ));
myList.Add( new Person( 3 , " EmersonFacunte " ));
// find a specific object
Person myLocatedObject = myList.Find( delegate (Person p) { return p.ID == 1 ; });
}
备注:在list和array集合中搜索元素经常使用该方法,主要技术是泛型委托
list用法注意:如果增加一个对象,必须重新new一个对象,看下面的例子:
person p = new pewson();
for ( int i = 0 ;i < 5 ;i ++ )
{
p.ID = i;
p.Name = " xxxx " ;
list.add(p);
}
for ( int i = 0 ;i < 5 ;i ++ )
{
person p = new person();
p.ID = i;
p.Name = " xxxx " ;
list.add(p);
}
上面有区别吗?在输出list的值是有区别了,第一个list里面存放的都是一样的,结果和最后一个一样,都是同一个人对象,第二个list达到预期的效果,存储不同的人对象。这是为什么?原因很简单,一个list对象中存储的都是对一个共有的对象进行引用,所以以最后改变的值为准。
对象的排序:本文主要阐述对存储datatable的list进行按TableName排序
1、新建一个sort类
public class SceneSort:IComparer < DataTable >
{
public int Compare(DataTable obj1, DataTable obj2)
{
int tableNameLength1;
int tableNameLength2;
if (obj1 == null )
{
if (obj2 == null )
return 0 ;
else
return - 1 ;
}
else
{
if (obj2 == null )
return 1 ;
else
{
tableNameLength1 = obj1.TableName.Length;
tableNameLength2 = obj2.TableName.Length;
if (Convert.ToInt32(obj1.TableName.Substring( 2 ,tableNameLength1 - 2 )) > Convert.ToInt32(obj2.TableName.Substring( 2 ,tableNameLength2 - 2 )))
return 1 ; // 大于返回1
else if (Convert.ToInt32(obj1.TableName.Substring( 2 ,tableNameLength1 - 2 )) < Convert.ToInt32(obj2.TableName.Substring( 2 ,tableNameLength2 - 2 )))
return - 1 ; // 小于返回-1
else
return 0 ; // 相等返回0
}
}
}
2 排序:
List < DataTable > ldt = new List < DataTable > ();
SceneSort ss = new SceneSort ();
tablelist.sort(ss);即可对list进行排序;
本文来自CSDN博客,转载请标明出处:http://blog.csdn.net/cxb_wind/archive/2008/04/10/2277670.aspx