单链表的合并（c++实现）

场景：

两个非递减单链表合并为一个非递减单链表

例如：{1,3,6,8}和{2,3,7,9,11,13}合并为{1,2,3,3,6,7,8,9,11,13}

---

代码：

提示：需考虑当一个表满后，将另一个表的剩余结点直接移到新链表。

#include 

typedef struct LNode{
    int data;
    struct LNode *next;
}LNode;

void createLinkList(LNode *&head);
void showLinkList(LNode *head);
void mergeLinkList(LNode *head1, LNode *head2, LNode *&head3);
using namespace std;

int main(){
    LNode *h1,*h2,*h3;
    //连续创建三个表
    createLinkList(h1);
    createLinkList(h2);
    createLinkList(h3);
    //展示创建结果
    showLinkList(h1);
    showLinkList(h2);
    showLinkList(h3);
    //合并h1,h2到h3
    mergeLinkList(h1, h2, h3);
    //展示合并结果
    showLinkList(h3);
    return 0;
}

void createLinkList(LNode *&head){
    head = (LNode*)malloc(sizeof (LNode));
    head->next=nullptr;
    int data;
    LNode *p,*tail=head;
    cout << "**********尾插法**********（退出值：9999）" << endl;
    while(true){
        cout << "请输入结点的值：";
        cin >> data;
        if(data == 9999){
            break;
        }
        p = (LNode*)malloc(sizeof (LNode));
        tail->next = p;
        p->data = data;
        p->next = nullptr;
        tail = p;
    }
    cout << "结束成功！" << endl;
}

void showLinkList(LNode *head){
    cout << "【";
    int flag = 0;
    while(head->next!= nullptr){
        if(flag==0){
            head = head->next;
            cout << head->data;
            flag = 1;
        }
        if(head->next== nullptr){
            break;
        }
        head = head->next;
        cout << " " << head->data;
    }
    cout << "】" << endl;
    cout << "打印完毕！" << endl;
}

void mergeLinkList(LNode *head1, LNode *head2, LNode *&head3){
    if(head1->next== nullptr){
        head3 = head2;
        return;
    }
    if(head2->next== nullptr){
        head3 = head1;
        return;
    }
    head1 = head1->next;
    head2 = head2->next;
    LNode *tail = head3;
    while(true){
        if(head1->data>head2->data){
            do {
                LNode *p;
                p = (LNode*)malloc(sizeof (LNode));
                tail->next = p;
                p->next = nullptr;
                p->data = head2->data;
                head2 = head2->next;
                tail = tail->next;
                tail->next = nullptr;
            }while(head2!= nullptr && head1->data>head2->data);
            if(head2== nullptr){
                while(head1!= nullptr){
                    LNode *p;
                    p = (LNode*)malloc(sizeof (LNode));
                    tail->next = p;
                    p->next = nullptr;
                    p->data = head1->data;
                    head1 = head1->next;
                    tail = tail->next;
                    tail->next = nullptr;
                }
                break;
            }
        }else{
            do {
                LNode *p;
                p = (LNode*)malloc(sizeof (LNode));
                tail->next = p;
                p->next = nullptr;
                p->data = head1->data;
                head1 = head1->next;
                tail = tail->next;
                tail->next = nullptr;
            }while(head1!= nullptr && head1->data<=head2->data);
            if(head1== nullptr){
                while(head2!= nullptr){
                    LNode *p;
                    p = (LNode*)malloc(sizeof (LNode));
                    tail->next = p;
                    p->next = nullptr;
                    p->data = head2->data;
                    head2 = head2->next;
                    tail = tail->next;
                    tail->next = nullptr;
                }
                break;
            }
        }
    }
}

---

结果截图：

图1：插值建立两个新链表 

 

图2：新链表只建立，不插值