C语言蓝桥杯刷题：组队

题目链接

解题思路：这题看上去怪吓人，其实就是暴力求解，把每种情况遍历一下比较即可。因为它只有5个位置，每个位置20个人，也就是遍历20^5，暴力求解还是能通过的，代码如下。

//组队
#include 
#include 

int main(int argc, char *argv[])
{
	// 请在此输入您的代码
	int i, j, k, l, m;//分别标记1-5号位的各个选手,比如i标记1号位的1-20个选手
	int arr[5][20] = {
	  {97,92,0,0,89,82,0,0,0,95,0,0,94,0,0,0,98,93,0,0},
	  {90,85,0,0,83,86,0,97,0,99,0,0,91,83,0,0,83,87,0,99},
	  {0,96,0,0,97,0,0,96,89,0,96,0,0,87,98,0,99,92,0,96},
	  {0,0,0,80,0,0,87,0,0,0,97,93,0,0,97,93,98,96,89,95},
	  {0,0,93,86,0,0,90,0,0,0,0,98,0,0,98,86,81,98,92,81}
	};//arr[a][b]表示a+1号位，b号选手的评分,比如arr[0][9]为1号位9号选手评分
	int max = 0;
	for (i = 0;i < 20;i++)
	{
		for (j = 0;j < 20;j++)
		{
			for (k = 0;k < 20;k++)
			{
				for (l = 0;l < 20;l++)
				{
					for (m = 0;m < 20;m++)
					{
						//要保证一个选手只能担任一个位置
						if (i != j && i != k && i != l && i != m && j != k && j != l && j != m && k != l && k != m && l != m)
						{
							int tmp = arr[0][i] + arr[1][j] + arr[2][k] + arr[3][l] + arr[4][m];
							if (tmp > max)
							{
								max = tmp;
							}
						}
					}
				}
			}
		}
	}
	printf("%d", max);
	return 0;
}