for循环语句

'''

1 .if else 循环语句

x = int(input('输入学员分数:'))

if x >90:

print('A')

elif x >=80:

print('B')

elif x >=60:

print('C')

else:

print('不合格')

2. 逻辑判断语句

a = 19

if a >=0 and a <= 15:

print('yes')

b = 20

if b < 0 or b< 10:

print('yes')

elif b>50:

print('hhh')

else:

print('no')

3.连续判断 设定条件

x = int (input("输入学员分数:"))

if x > 0 and x <=100:

if x > 90:

print('A')

elif x >=80:

print('B')

elif x >= 60:

print('C')

else:

print('D')

else:

print('您的输入有误')

4.判断语句

第一题

x = int (input("请输入数字1-7"))

if x == 1:

print('今天是星期一')

elif x == 2:

print('今天是星期二')

elif x == 3:

print('今天是星期三')

elif x == 4:

print('今天是星期四')

elif x == 5:

print('今天是星期五')

elif x == 6:

print('今天是星期6')

else :

print('今天是星期日')

第二题

a = int(input('请输入一个数字'))

b = int(input('请输入二个数字'))

if a>b:

print('a比b大')

else:

print('a比b小')

第三题

x = int(input('请输入一个年份'))

if  x % 400 == 0:

print('闰年')

elif x % 4 == 0 and x % 100 !=0:

print('闰年')

else:

print('不是闰年')

第四题

xx = input('请输入用户名')

xy = int(input('请输入密码'))

if xx == 'rongda' and xy == 123:

print('登陆成功')

else:

print("登陆失败")

第五题

x = int(input('请输入三位数'))

a = x//100

b = (x//10-x//100*10)

c = (x - x//10*10)

if a**3+b**3+c**3 == x:

print('水仙花数字')

else:

print('非理想数字')

循环语句

count = 0

while count <= 10:

print('这个数字是:', count)

count = count +1

print(count)

a = 0

while a < 5:

print(a,'小于5')

a = a + 1

else:

print(a,'小于5')

b = 1

while b < 5:print(b+1,'b小于5')  ??

a=0

s = 0

while a < 100 :

a=a+1

s+=a

print(s)

a = 1

while a <100:

if a %2 ==1:

print(a,end=',')

a += 1  #第二行也今可以换但是不一样了?

For循环!!!

for i in '成为像最好的':

print(i)

lt = ['贵州茅台','五粮液','沱牌舍得']

for i in lt:

print(i)

lt = ['清华','北大青鸟','蓝翔','新东方']

for i in range(len(lt)):

print(lt[i])

lt = (1,3,'学校',[8,9,1])

for i in range(len(lt)): #len()后面是圆括号

print(lt[i])

d = {'name':'张三','age':'30','habby':'学习','dream':'没有'}

for x ,y in d.items():

print(x,y)

for i in range(0,101,2):

print(i,end=' ')

x={}

for a,b in x.items():

print(a,b)

第一种做法

a = 1

b = 0

while a<100 :

b += a

a =a+2

# print(b)

c = 0

d = 0

while c<100 :

d += c

c =c+2

s=b-d

print(s)

第二种做法

x =0

y=0

for i1 in range(1,100,2):

x+=i1

for i2 in range(2, 100, 2):

y+=i2

s=x-y

print(s)

13亿人口多少年后到达26亿?

a =13

year =0

while a<=26:

a*=1.008

year+=1

else:

print('%d年后到达26亿'%year)

试验: while循环  等等

a = 0

while a <100:

if a %2 ==0:

print(a, end=',')

a = 1

while a <10:

if a %2 ==1:

a += 1

print(a, end=',')  第二行也今可以换但是不一样了?

显示 错误:IndentationError: expected an indented block

持续卡机 无法验证 字符逻辑

'''

result =0

m =0

b =3

while m <99:#会加一个数字所以提前减去一个数 且 m是不是符合实际情况?

    m +=1

    if m%2==1:

result += m

else:

result -= m

print(result)