script interactivating with sftp

write a shell script，its function is：
1 get all files from remote sftp server
2 check the created time of file
3 remove the files before a specified time

Here's an example shell script that achieves the functionality you described using the sftp command and the find command:bash
Copy code

#!/bin/bash

# Set variables
REMOTE_USER="username"
REMOTE_HOST="remote_host"
REMOTE_PATH="/path/to/files"
LOCAL_PATH="/local/path"
CUTOFF_TIME=$(date -d "1 week ago" +"%s") # Files created before this time will be removed

# Connect to remote SFTP server and get list of files
sftp $REMOTE_USER@$REMOTE_HOST << EOF
  cd $REMOTE_PATH
  ls -l
  bye
EOF

# Parse output of 'ls -l' command to get list of files and their creation times
FILES=$(sftp $REMOTE_USER@$REMOTE_HOST << EOF
  cd $REMOTE_PATH
  ls -l
  bye
EOF
)
FILES_ARR=($FILES)
FILES_COUNT=${#FILES_ARR[@]}
FILES_LIST=""
for (( i=0; i<$FILES_COUNT; i+=9 )); do
  FILE_TIME=$(date -d "${FILES_ARR[$i+5]} ${FILES_ARR[$i+6]} ${FILES_ARR[$i+7]}" +"%s")
  if [[ $FILE_TIME -lt $CUTOFF_TIME ]]; then
    FILES_LIST+="${FILES_ARR[$i+8]}\n"
  fi
done

# Remove files before specified time
if [[ -n "$FILES_LIST" ]]; then
  echo "Removing the following files:"
  echo -e "$FILES_LIST"
  find $LOCAL_PATH -type f -name "$FILES_LIST" -delete
else
  echo "No files found to remove."
fi

In this script, you would need to replace the REMOTE_USER, REMOTE_HOST, REMOTE_PATH, and LOCAL_PATH variables with the appropriate values for your SFTP server and local machine. You may also want to adjust the CUTOFF_TIME variable to the desired time limit for file deletion.

To run this script, save it to a file (e.g. remove_old_files.sh) and make it executable using the command chmod +x remove_old_files.sh. Then, run the script using the command ./remove_old_files.sh.