python123 ios_用Python为iOS10生成图标和截屏
简介
这两天更新完Xcode8之后发现Xcode对图标的要求又有了变化，之前用的一个小应用“IconKit”还没赶上节奏，已经不能满足Xcode8的要求了。
于是就想起来用Python自己做个脚本来生成图标。
其实这个脚本很早就写了，现在为了适应iOS10，就修改完善下，并且放到了GitHub。
可以看看效果图：
代码：#encoding=utf-8
#by 不灭的小灯灯
#create date 2016/5/22
#update 2016/9/21
#support iOS 10
#site www.winterfeel.com
import os
import sys
from PIL import Image
iosSizes = ['20@1x','20@2x','20@3x','29@1x','29@2x','29@3x','40@1x','40@2x','40@3x','60@2x','60@3x','60@3x','76@1x','76@2x','167@1x']
androidSizes = [32,48,72,96,144,192]
androidNames = ['ldpi','mdpi','hdpi','xhdpi','xxhdpi','xxxhdpi']
sizesiOS = [(640,960),(640, 1136),(750, 1334),(1242, 2208),(1536, 2048),(2048, 2732)]
foldersiOS = ['iPhone4s','iPhone5','iPhone6','iPhone6plus','iPad','iPadLarge']
sizesAndroid = [(480,800),(720,1280),(1080,1920)]
foldersAndroid = ['480x800','720x1280','1080x1920']
def processIcon(filename,platform):
icon = Image.open(filename).convert("RGBA")
if icon.size[0] != icon.size[1]:
print 'Icon file must be a rectangle!'
return
if platform == 'android':
#安卓圆角
mask = Image.open('mask.png')
r,g,b,a = mask.split()
icon.putalpha(a)
if not os.path.isdir('androidIcon'):
os.mkdir('androidIcon')
index = 0
for size in androidSizes:
im = icon.resize((size,size),Image.BILINEAR)
im.save('androidIcon/icon-'+ androidNames[index]+'.png')
index = index + 1
else:
if not os.path.isdir('iosIcon'):
os.mkdir('iosIcon')
for size in iosSizes:
originalSize = int(size.split('@')[0])#原始尺寸
multiply = int(size.split('@')[1][0:1])#倍数
im = icon.resize((originalSize*multiply,originalSize*multiply),Image.BILINEAR)
im.save('iosIcon/icon'+size+'.png')
print 'Congratulations!It\'s all done!'
def walk_dir(dir,platform):
files = os.listdir(dir)
for name in files:
if name.split('.')[-1] == 'jpg' or name.split('.')[-1] == 'png':#处理jpg和png
produceImage(name,platform)
print 'Congratulations!It\'s all done!'
def produceImage(filename,platform):
print 'Processing:' + filename
img = Image.open(filename)
index = 0
sizes = sizesiOS
folders = foldersiOS
if platform == 'android':#默认ios，如果是安卓
sizes = sizesAndroid
folders = foldersAndroid
for size in sizes:
if not os.path.isdir(folders[index]):
os.mkdir(folders[index])
if img.size[0] > img.size[1]:#如果是横屏，交换坐标
im = img.resize((size[1],size[0]),Image.BILINEAR)
im.save(folders[index]+'/'+filename)
else:
im = img.resize(size,Image.BILINEAR)
im.save(folders[index]+'/'+filename)
index = index + 1
action = sys.argv[1]#action:icon or screenshot
if action == 'screenshot':
platform = sys.argv[2]#platform
if platform == 'ios':
walk_dir('./','ios')
elif platform == 'android':
walk_dir('./','android')
else:
print 'Hey,Platform can only be "ios" or "android" !'
elif action == 'icon':
filename = sys.argv[2]#image filename
platform = sys.argv[3]#platform
if not os.path.exists(filename):
print 'Hey,File Not Found!'
else:
if platform == 'ios':
processIcon(filename,'ios')
elif platform == 'android':
processIcon(filename,'android')
else:
print 'Hey,Platform can only be "ios" or "android" !'
else:
print 'Hey,action can only be "icon" or "screenshot" !'
脚本环境要求
Python 2.7
PIL or Pillow
笔者亲测，也许是笔者太菜，试了各种方法安装PIL总是出错，最后还是用了Pillow，效果一样的。
怎么使用脚本
在Windows的命令行或者Mac的终端，输入:python tool.py [action] [filename] [platform]action：icon 或者 screenshot
filename：图标文件名，截屏不需要文件名，自动遍历
platform：ios 或者 android
举一些例子:生成iOS的图标：python tool.py icon icon.jpg ios
生成安卓的图标：python tool.py icon icon.jpg android
生成iOS的截屏：python tool.py screenshot ios
生成安卓的截屏：python tool.py screenshot android
注意注意生成安卓圆角图标需要一张PNG来裁剪，尺寸512x512，70圆角，GitHub中已经附带。
生成截屏时会自动遍历所有JPG和PNG文件，自动识别横竖屏
结语
如果你觉得有用，欢迎在GitHub中Star一下，也欢迎改进，代码简单易懂加了注释。