方法一: Wait/Notify
public class Print {
boolean currentA = false;
public synchronized void printA() {
if (!currentA) {
try {
System.out.println("wait here");
this.wait();
} catch (Exception e) {
e.printStackTrace();
}
}
currentA = false;
System.out.println("current Thread A:" + Thread.currentThread());
this.notify();
}
public synchronized void printB() {
if (currentA) {
try {
System.out.println("wait b here");
this.wait();
} catch (Exception e) {
e.printStackTrace();
}
}
currentA = true;
System.out.println("current Thread B:" + Thread.currentThread());
this.notify();
}
public static void main(String[] args) {
Print p = new Print();
new Thread(new Runnable() {
@Override
public void run() {
for (int i = 0; i < 10; i++) {
p.printA();
}
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
for (int i = 0; i < 10; i++) {
p.printB();
}
}
}).start();
}
}
这里利用的是synchronized持有对象锁的特点,对于同样一个实例对象,同时只有一个线程可以进入对象内部执行方法,这样变相实现互斥的功能。但是利用的是重量级锁,也就是同步锁,虽然有锁升级的过程,但是性能还是比较低。下面用volatile 进行优化
方法二:自旋+volatile
**
* @program: test
* @description:
* @author: Mr.Wang
* @create: 2022-01-11 15:24
**/
public class Print {
volatile int num = 0;
public void printA() {
while (num % 2 ==0) {
// Thread.yield();
}
num++;
System.out.println("current Thread A:" + Thread.currentThread()+num);
}
public void printB() {
if (num%2 !=0) {
try {
// Thread.yield();
} catch (Exception e) {
e.printStackTrace();
}
}
num++;
System.out.println("current Thread B:" + Thread.currentThread()+num);
}
public static void main(String[] args) {
Print p = new Print();
new Thread(new Runnable() {
@Override
public void run() {
for (int i = 0; i < 50; i++) {
p.printA();
}
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
for (int i = 0; i < 50; i++) {
p.printB();
}
}
}).start();
}
}
利用了volitile的内存可见性的特点,但是使用了自旋,比较消耗CPU资源
方法三:lock
import java.util.concurrent.CountDownLatch;
import java.util.concurrent.CyclicBarrier;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;
/**
* @program: test
* @description:
* @author: Mr.Wang
* @create: 2022-01-11 15:24
**/
public class Print {
CountDownLatch countDownLatch = new CountDownLatch(1);
Lock lock = new ReentrantLock(true);
volatile int num = 0;
public void printA() {
lock.lock();
try {
num++;
System.out.println("current Thread A:" + Thread.currentThread()+num);
}catch (Exception e){
}finally {
lock.unlock();
}
}
public void count(){
countDownLatch.countDown();
}
public void printB() {
lock.lock();
try {
num++;
System.out.println("current Thread B:" + Thread.currentThread()+num);
}catch (Exception e){
}finally {
lock.unlock();
}
}
public static void main(String[] args) {
Print p = new Print();
new Thread(new Runnable() {
@Override
public void run() {
try{
p.countDownLatch.await();
}catch (Exception e){
e.printStackTrace();
}
for (int i = 0; i < 50; i++) {
p.printA();
}
}
}).start();
new Thread(new Runnable() {
@Override
public void run() {
p.count();
for (int i = 0; i < 50; i++) {
p.printB();
}
}
}).start();
}
注意这里我试用了公平锁,避免同一个线程多次获取锁的情况来实现顺序打印,同时使用
countDownLatch让两个线程同时开始
方法四: Condition
public class Print {
private static Lock lock = new ReentrantLock();
private static Condition A = lock.newCondition();
private static Condition B = lock.newCondition();
private static Condition C = lock.newCondition();
private volatile static int count = 0;
private static int sum=1;
static class ThreadA extends Thread {
@Override
public void run() {
try {
lock.lock();
for (int i = 0; i < 10; i++) {
if (count % 3 != 0){//注意这里是不等于0,也就是说没轮到该线程执行,之前一直等待状态
A.await(); //该线程A将会释放lock锁,构造成节点加入等待队列并进入等待状态
}
System.out.println("-------第"+sum+"次--------");
System.out.println("A");
count++;
B.signal(); // A执行完唤醒B线程
}
} catch (InterruptedException e) {
e.printStackTrace();
} finally {
lock.unlock();
}
}
}
static class ThreadB extends Thread {
@Override
public void run() {
try {
lock.lock();
for (int i = 0; i < 10; i++) {
if (count % 3 != 1)
B.await();// B释放lock锁,当前面A线程执行后会通过B.signal()唤醒该线程
System.out.println("B");
count++;
C.signal();// B执行完唤醒C线程
}
} catch (InterruptedException e) {
e.printStackTrace();
} finally {
lock.unlock();
}
}
}
static class ThreadC extends Thread {
@Override
public void run() {
try {
lock.lock();
for (int i = 0; i < 10; i++) {
if (count % 3 != 2)
C.await();// C释放lock锁
System.out.println("C");
count++;
sum++;
A.signal();// C执行完唤醒A线程
}
} catch (InterruptedException e) {
e.printStackTrace();
} finally {
lock.unlock();
}
}
}
public static void main(String[] args) throws InterruptedException {
new ThreadA().start();
new ThreadB().start();
new ThreadC().start();
}
}