uniapp 按时间排序当前以后七天时间

前两天做了一个项目预约时需要处理未来一周日期；就用原生js整了一个虽然有点繁琐，但能用

直接先看效果吧

 接下来看怎么实现的

先获取当前日期并将其转换成xxx-xx-xx的格式

 然后声明一个数组在其放入星期

然后根据当前日期获取当前周几（周日开始；周日为0；周一为1）；

并根据次来截取日期

 

 然后再创建两个数组将其放入数组中并匹配就可以了——完整代码奉上

let that = this;
				// 获取当前的日期
				var now = new Date();

				// 从日期对象中获取年份、月份和日期
				var year = now.getFullYear();
				var month = now.getMonth() + 1;
				var day = now.getDate();
				that.day = day;
				// 将年份、月份和日期拼接成字符串yyyy-mm-dd格式
				var dateStr = year + '年' + month + '月' + day + '日';
				that.time = dateStr;
				const timestamp = Date.now();
				const date = new Date(timestamp);
				const dayOfWeek = ['周日', '周一', '周二', '周三', '周四', '周五', '周六'][date.getDay()];
				// console.log(num,"num");
				let week = that.monday;
				let weeks = that.monday;
				let daynum = date.getDay();
				let obj = week.splice(0, daynum);
				// console.log(obj);
				let objs = weeks.splice(daynum, 6);
				let lobg = [];
				for (let i = 0; i < num.length; i++) {
					lobg.push(num[i]);
				}
				for (let i = 0; i < objs.length; i++) {
					lobg.push(objs[i]);
				}
				for (let i = 0; i < obj.length; i++) {
					lobg.push(obj[i]);
				}
				that.week = lobg;
				let today = new Date();
				// 创建一个空数组来存储未来一周的日期
				let futureDates = [];
				let timeDay = [];
				// 循环七次，每次增加一天并将其添加到日期数组中
				for (let i = 0; i < 7; i++) {
					let futureDate = new Date(today.getTime() + (i * 24 * 60 * 60 * 1000));
					// 格式化日期为字符串，并添加到数组中
					futureDates.push(`${futureDate.getDate().toString().padStart(2, '0')}`);
					timeDay.push(
						`${futureDate.getFullYear()}-${(futureDate.getMonth() + 1).toString().padStart(2, '0')}-${futureDate.getDate().toString().padStart(2, '0')}`
					)
				}
				this.day = futureDates;
				this.timeDay = timeDay;