数据预处理,自己用二维数组模拟一个键盘
#include
#include
using namespace std;
int main()
{
char keyboard[8][4] = { {'a','b','c','0'},{'d','e','f','0'},{'g','h','i','0'},{'j','k','l','0'},{'m','n','o','0'},{'p','q','r','s'},{'t','u','v','0'},{'w','x','y','z'} };
string input;
while (cin >> input) {
int sum = 0;
int lastkey = -1;
for (int n = 0; n < input.length(); n++) {
int i;
int j;
for (i = 0; i < 8; i++) {
for (j = 0; j < 4; j++) {
if (input[n] == keyboard[i][j]) break;
}
if (j != 4 && input[n] == keyboard[i][j]) break;
}
if (lastkey == i) {
sum += j + 1 + 2;
}
else {
sum += j + 1;
}
lastkey = i;
}
cout << sum << endl;
}
}