方法一:
定义一个函数 to_bin
def to_bin(value, num):#十进制数据,二进制位宽
bin_chars = ""
temp = value
for i in range(num):
bin_char = bin(temp % 2)[-1]
temp = temp // 2
bin_chars = bin_char + bin_chars
return bin_chars.upper()#输出指定位宽的二进制字符串
调用该函数示例:
out_bin = to_bin(10,8)#不带"0b"
out_bin = "0b" + out_bin #带"0b",和python内置函数bin输出格式一致,字符串开头带"0b"
方法二:
o_bin = bin(10)[2:] #转换为二进制,并且去掉“0b”
out_bin = o_bin.rjust(8,'0') #原字符串右侧对齐, 左侧补零,补齐后总位宽为8 #不带"0b"
out_bin = "0b" + out_bin #带"0b",和python内置函数bin输出格式一致,字符串开头带"0b"
以上为原创,其他关于Python进制转换(二进制、十进制和十六进制)参考如下代码:
转载自https://www.cnblogs.com/zhangpengshou/archive/2012/03/12/2392068.html
import os,sys
# global definition
# base = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F]
base = [str(x) for x in range(10)] + [ chr(x) for x in range(ord('A'),ord('A')+6)]
# bin2dec
# 二进制 to 十进制: int(str,n=10)
def bin2dec(string_num):
return str(int(string_num, 2))
# hex2dec
# 十六进制 to 十进制
def hex2dec(string_num):
return str(int(string_num.upper(), 16))
# dec2bin
# 十进制 to 二进制: bin()
def dec2bin(string_num):
num = int(string_num)
mid = []
while True:
if num == 0: break
num,rem = divmod(num, 2)
mid.append(base[rem])
return ''.join([str(x) for x in mid[::-1]])
# dec2hex
# 十进制 to 八进制: oct()
# 十进制 to 十六进制: hex()
def dec2hex(string_num):
num = int(string_num)
mid = []
while True:
if num == 0: break
num,rem = divmod(num, 16)
mid.append(base[rem])
return ''.join([str(x) for x in mid[::-1]])
# hex2tobin
# 十六进制 to 二进制: bin(int(str,16))
def hex2bin(string_num):
return dec2bin(hex2dec(string_num.upper()))
# bin2hex
# 二进制 to 十六进制: hex(int(str,2))
def bin2hex(string_num):
return dec2hex(bin2dec(string_num))