Python将十进制数据转换为指定位宽的二进制字符串的方法

方法一:
定义一个函数 to_bin

def to_bin(value, num):#十进制数据,二进制位宽
	bin_chars = ""
	temp = value
	for i in range(num):
		bin_char = bin(temp % 2)[-1]
		temp = temp // 2
		bin_chars = bin_char + bin_chars
	return bin_chars.upper()#输出指定位宽的二进制字符串

调用该函数示例:

out_bin = to_bin(10,8)#不带"0b"
out_bin = "0b" + out_bin #带"0b",和python内置函数bin输出格式一致,字符串开头带"0b"

方法二:

o_bin = bin(10)[2:] #转换为二进制,并且去掉“0b”
out_bin = o_bin.rjust(8,'0') #原字符串右侧对齐, 左侧补零,补齐后总位宽为8 #不带"0b"
out_bin = "0b" + out_bin #带"0b",和python内置函数bin输出格式一致,字符串开头带"0b"

以上为原创,其他关于Python进制转换(二进制、十进制和十六进制)参考如下代码:
转载自https://www.cnblogs.com/zhangpengshou/archive/2012/03/12/2392068.html

import os,sys  
  
# global definition  
# base = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F]  
base = [str(x) for x in range(10)] + [ chr(x) for x in range(ord('A'),ord('A')+6)]  
  
# bin2dec  
# 二进制 to 十进制: int(str,n=10)   
def bin2dec(string_num):  
    return str(int(string_num, 2))  
  
# hex2dec  
# 十六进制 to 十进制  
def hex2dec(string_num):  
    return str(int(string_num.upper(), 16))  
  
# dec2bin  
# 十进制 to 二进制: bin()   
def dec2bin(string_num):  
    num = int(string_num)  
    mid = []  
    while True:  
        if num == 0: break  
        num,rem = divmod(num, 2)  
        mid.append(base[rem])  
  
    return ''.join([str(x) for x in mid[::-1]])  
  
# dec2hex  
# 十进制 to 八进制: oct()   
# 十进制 to 十六进制: hex()   
def dec2hex(string_num):  
    num = int(string_num)  
    mid = []  
    while True:  
        if num == 0: break  
        num,rem = divmod(num, 16)  
        mid.append(base[rem])  
  
    return ''.join([str(x) for x in mid[::-1]])  
  
# hex2tobin  
# 十六进制 to 二进制: bin(int(str,16))   
def hex2bin(string_num):  
    return dec2bin(hex2dec(string_num.upper()))  
  
# bin2hex  
# 二进制 to 十六进制: hex(int(str,2))   
def bin2hex(string_num):  
    return dec2hex(bin2dec(string_num))

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