java 多个日期集合中连续的日期放在一组

我们有一个需求，一个日期集合，连续的放在一组。

源代码：

Long toEpochMilli(String date) {
        return LocalDate.parse(date, DateTimeFormatter.ofPattern("yyyy-MM-dd")).atStartOfDay().atZone(ZoneId.systemDefault()).toInstant().toEpochMilli();
    }

    String toDate(Long value) {
        java.util.Date d = Date.from(Instant.ofEpochMilli(value));
        return new SimpleDateFormat("yyyy-MM-dd").format(d);
    }

    @Test
    public void continuousTest() {
        //int[] srcArray = new int[]{1, 3, 4, 5, 6, 7, 8, 12, 13, 14};
        List<String> origins = Arrays.asList("2023-01-01", "2023-01-04", "2023-01-05", "2023-01-06", "2023-01-31", "2023-02-01", "2023-02-02");
        List<Long> time = origins.stream().map(each -> toEpochMilli(each)).collect(Collectors.toList());
        Long[] srcArray = time.toArray(new Long[0]);
        List<List<String>> allList = new ArrayList<>();
        //List> dateList = new ArrayList<>();
        for (int i = 0; i < srcArray.length; i++) {
            List<String> tmpList = new ArrayList<>();
            for (int j = i; j < srcArray.length; j++) {
                tmpList.add(toDate(srcArray[j]));
                if (j + 1 == srcArray.length || srcArray[j + 1] - srcArray[j] != 86400000) {
                    allList.add(tmpList);
                    i = j;
                    break;
                }
            }
        }
        System.out.println(allList);
    }

Console

[[2023-01-01], [2023-01-04, 2023-01-05, 2023-01-06], [2023-01-31, 2023-02-01, 2023-02-02]]