Codeforces Round 890 (Div. 2) supported by Constructor Institute C. To Become Max

Codeforces Round 890 (Div. 2) supported by Constructor Institute
C. To Become Max

Code:

#include 
#include 
using namespace std;
const int maxn = 1010;
int a[maxn];
int n,k;

int check(int i, int mid, int k){
	if(i>n||k<0) return 0;
	int used = max(0, mid-a[i]);
	if(a[i] >= mid) return 1;
	else return check(i+1, mid-1, k-used);
}

int main(){
	int t;
	cin >> t;
	while(t--){
		cin >> n >> k;
		for(int i = 1;i <= n;i++){
			cin >> a[i];
		}
		int ans = 0;
		for(int i = 1;i <= n;i++){
			int l = 0;
			int r = 1e9;
			while(l <= r){
				int mid = (l+r)/2;
				if(check(i, mid, k)) l = mid+1;
				else r = mid-1;
			}
			ans = max(ans, l-1);
		}
		cout << ans << endl;
	}
	return 0;
}