com.alibaba.fastjson.JSONArray cannot be cast to java.util.ArrayList

问题:

  public xxxcountOfType(Map map){


        System.out.println("前端穿的ownerId是:" + map.get("ownerId") );
        System.out.println("前端穿的数组是" + map.get("list"));
        Object ownerId = map.get("ownerId");
        ArrayList ids = (ArrayList)map.get("list");    
        ......
    }

代码运行到ArrayList ids = (ArrayList)map.get("list");语句提示

io.openflat.core.ApiInvoker.caugthException(ApiInvoker.java:185) com.alibaba.fastjson.JSONArray cannot be cast to java.util.ArrayList

前端传参:


                        method: 'post',
                        name: 'xxxx.countOfType',                       
                        async: false,
                        data:{'list':me.ids,'ownerId':data[0].ownerId},

解决办法

方法1:

将ArrayList ids = (ArrayList)map.get("list");

改为List ids = (List)map.get("list");

方法2:

将ArrayList ids = (ArrayList)map.get("list");

改为

ArrayList ids = JSONObject.parseObject(JSONObject.toJSONString(map.get("list")),ArrayList.class);

方法3:使用TypeReference

将ArrayList ids = (ArrayList)map.get("list");

改为

ArrayList ids = JSONObject.parseObject(map.get("list").toString(),new TypeReference>(){});

Java中TypeReference用法说明

原文链接:https://blog.csdn.net/zhuzj12345/article/details/102914545

用途

在使用fastJson时,对于泛型的反序列化很多场景下都会使用到TypeReference,例如:

void testTypeReference() {
        List list = new ArrayList<>();
        list.add(1);
        list.add(9);
        list.add(4);
        list.add(8);
        JSONObject jsonObj = new JSONObject();
        jsonObj.put("a", list);
        System.out.println(jsonObj);
 
        List list2 = jsonObj.getObject("a", new TypeReference>(){});
 
        System.out.println(list2);
    }

输出

1{"a":[1,9,4,8]}
2[1, 9, 4, 8]

使用TypeReference可以明确的指定反序列化的类型,具体实现逻辑参考TypeReference的构造函数 

protected TypeReference(){
        Type superClass = getClass().getGenericSuperclass();
 
        Type type = ((ParameterizedType) superClass).getActualTypeArguments()[0];
 
        Type cachedType = classTypeCache.get(type);
        if (cachedType == null) {
            classTypeCache.putIfAbsent(type, type);
            cachedType = classTypeCache.get(type);
        }
 
        this.type = cachedType;
    }

解说

其中核心的方法是:getActualTypeArguments,它可以得到父类的反省类型

ParameterizedType是一个记录类型泛型的接口, 继承自Type,一共三方法:

  • Type[] getActualTypeArguments(); //返回泛型类型数组
  • Type getRawType(); //返回原始类型Type
  • Type getOwnerType(); //返回 Type 对象,表示此类型是其成员之一的类型。

例如 Map 对应的ParameterizedType三个方法分别取值如下:

  • [class java.lang.String, class java.lang.String]
  • interface java.util.Map
  • null

例证

package JsonLearn;
 
import java.lang.reflect.ParameterizedType;
import java.lang.reflect.Type;
import java.util.HashMap;
import java.util.Map;
 
public class TypeReferencBaseLearn {
    public static class IntMap extends HashMap {}
 
    void test1() {
        IntMap intMap = new IntMap();
        System.out.println("getSuperclass:" + intMap.getClass().getSuperclass());
        System.out.println("getGenericSuperclass:" + intMap.getClass().getGenericSuperclass());
        Type type = intMap.getClass().getGenericSuperclass();
        if (type instanceof ParameterizedType) {
            ParameterizedType p = (ParameterizedType)type;
            for (Type t : p.getActualTypeArguments()) {
                System.out.println(t);
            }
        }
    }
 
    void test2() {
        Map intMap = new HashMap<>();
        System.out.println("\ngetSuperclass:" + intMap.getClass().getSuperclass());
        System.out.println("getGenericSuperclass:" + intMap.getClass().getGenericSuperclass());
        Type type = intMap.getClass().getGenericSuperclass();
        if (type instanceof ParameterizedType) {
            ParameterizedType p = (ParameterizedType)type;
            for (Type t : p.getActualTypeArguments()) {
                System.out.println(t);
            }
        }
    }
 
    void test3() {
        Map intMap = new HashMap(){};
        System.out.println("\ngetSuperclass:" + intMap.getClass().getSuperclass());
        System.out.println("getGenericSuperclass:" + intMap.getClass().getGenericSuperclass());
        Type type = intMap.getClass().getGenericSuperclass();
        if (type instanceof ParameterizedType) {
            ParameterizedType p = (ParameterizedType)type;
            for (Type t : p.getActualTypeArguments()) {
                System.out.println(t);
            }
        }
    }
 
    public static void main(String[] args) {
        TypeReferencBaseLearn obj = new TypeReferencBaseLearn();
        obj.test1();
        obj.test2();
        obj.test3();
    }
}

输出

getSuperclass:class java.util.HashMap
getGenericSuperclass:java.util.HashMap
class java.lang.String
class java.lang.Integer
 
getSuperclass:class java.util.AbstractMap
getGenericSuperclass:java.util.AbstractMap
K
V
 
getSuperclass:class java.util.HashMap
getGenericSuperclass:java.util.HashMap
class java.lang.String
class java.lang.Integer 

备注

FastJson的相关应用可参考:https://blog.csdn.net/beidaol/article/details/104491950

你可能感兴趣的:(com.alibaba.fastjson.JSONArray cannot be cast to java.util.ArrayList)