C语言编程题

 有一个字符串开头或结尾含有n个空格（“          abcdefg         ”）欲去掉前后空格，返回一个新字符串

#define _CRT_SECURE_NO_WARNINGS
#include 
#include 
#include 
#include 

int getCount11(char* str, int* pCount)
{
	int i, j = 0;
	char* p = str;
	int ncount = 0;
	if (str == NULL || pCount == NULL)
	{
		return -1;
	}

	i = 0;
	j = strlen(p) - 1;

	while (isspace(p[i]) && p[i] != '\0')
	{
		i++;
	}
	while (isspace(p[j]) && p[j] != '\0')
	{
		j--;
	}
	ncount = j - i + 1;


	*pCount = ncount;

	return 0;
}
//取出字符串前后的空格
int trimSpace(char* str, char* newstr)
{
	int i, j = 0;
	char* p = str;
	int ncount = 0;
	if (str == NULL || newstr == NULL)
	{
		printf("程序出错\n");
		return -1;
	}

	i = 0;
	j = strlen(p) - 1;

	while (isspace(p[i]) && p[i] != '\0')
	{
		i++;
	}
	while (isspace(p[j]) && p[j] != '\0')
	{
		j--;
	}
	ncount = j - i + 1;
	strncpy(newstr, str + i, ncount);
	newstr[ncount] = '\0';
	return 0;
	

}
int main()
{
	char* p = "      abcdefg    ";
	char buf[1024]={0};
	
	int num = 0;
	getCount11(p, &num);
	trimSpace(p,buf);
	printf("%d\n", num);
	printf("%s",buf);
}