tp5连接postgresql的方法以及解决会出现的bug

Tp5的连接步骤:

1、首先在database.php中配置pgsql连接信息：

2、你可能遇到的问题：could not find driver

出现这个原因是因为你的php没有安装pgsql的驱动，解决方法很简单，打开php.ini，将其中的

extension=php_pdo_pgsql.dll前的  分号去掉，重新启动。怎么看是否有pgsql的驱动呢？在控制器方法中执行   phpinfo() ； 可以通看PDO 项看是否配置。

3、不出意外的话还是有问题这是你需要复制一下代码到pgsql数据库运行，我用的是navicat，直接在navicat运行就好了。

CREATE OR REPLACE FUNCTION pgsql_type(a_type varchar) RETURNS varchar AS

$BODY$

DECLARE

    v_type varchar;

BEGIN

    IF a_type='int8' THEN

          v_type:='bigint';

    ELSIF a_type='int4' THEN

          v_type:='integer';

    ELSIF a_type='int2' THEN

          v_type:='smallint';

    ELSIF a_type='bpchar' THEN

          v_type:='char';

    ELSE

          v_type:=a_type;

    END IF;

    RETURN v_type;

END;

$BODY$

LANGUAGE PLPGSQL;

CREATE TYPE "public"."tablestruct" AS (

  "fields_key_name" varchar(100),

  "fields_name" VARCHAR(200),

  "fields_type" VARCHAR(20),

  "fields_length" BIGINT,

  "fields_not_null" VARCHAR(10),

  "fields_default" VARCHAR(500),

  "fields_comment" VARCHAR(1000)

);

CREATE OR REPLACE FUNCTION "public"."table_msg" (a_schema_name varchar, a_table_name varchar) RETURNS SETOF "public"."tablestruct" AS

$body$

DECLARE

    v_ret tablestruct;

    v_oid oid;

    v_sql varchar;

    v_rec RECORD;

    v_key varchar;

BEGIN

    SELECT

          pg_class.oid  INTO v_oid

    FROM

          pg_class

          INNER JOIN pg_namespace ON (pg_class.relnamespace = pg_namespace.oid AND lower(pg_namespace.nspname) = a_schema_name)

    WHERE

          pg_class.relname=a_table_name;

    IF NOT FOUND THEN

        RETURN;

    END IF;

    v_sql='

    SELECT

          pg_attribute.attname AS fields_name,

          pg_attribute.attnum AS fields_index,

          pgsql_type(pg_type.typname::varchar) AS fields_type,

          pg_attribute.atttypmod-4 as fields_length,

          CASE WHEN pg_attribute.attnotnull  THEN ''not null''

          ELSE ''''

          END AS fields_not_null,

          pg_attrdef.adsrc AS fields_default,

          pg_description.description AS fields_comment

    FROM

          pg_attribute

          INNER JOIN pg_class  ON pg_attribute.attrelid = pg_class.oid

          INNER JOIN pg_type  ON pg_attribute.atttypid = pg_type.oid

          LEFT OUTER JOIN pg_attrdef ON pg_attrdef.adrelid = pg_class.oid AND pg_attrdef.adnum = pg_attribute.attnum

          LEFT OUTER JOIN pg_description ON pg_description.objoid = pg_class.oid AND pg_description.objsubid = pg_attribute.attnum

    WHERE

          pg_attribute.attnum > 0

          AND attisdropped <> ''t''

          AND pg_class.oid = ' || v_oid || '

    ORDER BY pg_attribute.attnum' ;

    FOR v_rec IN EXECUTE v_sql LOOP

        v_ret.fields_name=v_rec.fields_name;

        v_ret.fields_type=v_rec.fields_type;

        IF v_rec.fields_length > 0 THEN

            v_ret.fields_length:=v_rec.fields_length;

        ELSE

            v_ret.fields_length:=NULL;

        END IF;

        v_ret.fields_not_null=v_rec.fields_not_null;

        v_ret.fields_default=v_rec.fields_default;

        v_ret.fields_comment=v_rec.fields_comment;

        SELECT constraint_name INTO v_key FROM information_schema.key_column_usage WHERE table_schema=a_schema_name AND table_name=a_table_name AND column_name=v_rec.fields_name;

        IF FOUND THEN

            v_ret.fields_key_name=v_key;

        ELSE

            v_ret.fields_key_name='';

        END IF;

        RETURN NEXT v_ret;

    END LOOP;

    RETURN ;

END;

$body$

LANGUAGE 'plpgsql' VOLATILE CALLED ON NULL INPUT SECURITY INVOKER;

COMMENT ON FUNCTION "public"."table_msg"(a_schema_name varchar, a_table_name varchar)

IS '获得表信息';

---重载一个函数

CREATE OR REPLACE FUNCTION "public"."table_msg" (a_table_name varchar) RETURNS SETOF "public"."tablestruct" AS

$body$

DECLARE

    v_ret tablestruct;

BEGIN

    FOR v_ret IN SELECT * FROM table_msg('public',a_table_name) LOOP

        RETURN NEXT v_ret;

    END LOOP;

    RETURN;

END;

$body$

LANGUAGE 'plpgsql' VOLATILE CALLED ON NULL INPUT SECURITY INVOKER;

COMMENT ON FUNCTION "public"."table_msg"(a_table_name varchar)

IS '获得表信息';

4、写到这里大致的问题已经解决了，但是需要说的是 ‘user’在postgresql中属于保留字段，需要避免。