求助Re:9

 

求助Re:9_第1张图片

求助Re:9_第2张图片


 

#include
#define ll long long
#define A 1100000
using namespace std;
ll lmax[A],lmin[A],rmax[A],rmin[A],a[A],tong[A],n;
ll work(ll l,ll r,ll mid){
    ll w=0;
    lmax[mid]=a[mid];lmin[mid]=a[mid];
    rmax[mid+1]=a[mid+1];rmin[mid+1]=a[mid+1];
    for(ll i=mid-1;i>=l;i--){
        lmax[i]=max(lmax[i+1],a[i]);
        lmin[i]=min(lmin[i+1],a[i]);
    }
    for(ll i=mid+2;i<=r;i++){
        rmax[i]=max(rmax[i-1],a[i]);
        rmin[i]=min(rmin[i-1],a[i]);
    }
    for(ll i=l;i<=mid;i++){
        ll j=i+lmax[i]-lmin[i];
        if(j>mid&&rmax[j]lmin[i]) w++;
    }
    ll p1=mid+1,p2=mid;
    while(p1<=r&&rmax[p1];
    while(p21]>lmin[l]) p2++,tong[rmax[p2]-p2]++;
    for(ll i=l;i<=mid;i++){
        while(p1>mid+1&&rmax[p1-1]>lmax[i]) p1--,tong[rmax[p1]-p1]++; 
        while(p2>mid&&rmin[p2];
        w+=max(tong[lmin[i]-i],0ll);
    }
    for(ll i=mid+1;i<=r;i++){
        tong[rmax[i]-i]=0;
    }
    return w;
}
ll solve(ll l,ll r){
    if(l==r) return 1;
    ll mid=(l+r)>>1;
    ll zz=solve(l,mid)+solve(mid+1,r);
    zz+=work(l,r,mid);
    reverse(a+l,a+r+1);
    if((r-l+1)&1) mid--;
    zz+=work(l,r,mid);
    reverse(a+l,a+r+1);
    return zz;
}
int main(){
    scanf("%lld",&n);
    for(ll i=1;i<=n;i++){
        ll xx,yy;
        scanf("%lld%lld",&xx,&yy);
        a[xx]=yy;
    }
    cout<1,n);
}

 

把tong放在a前面就AC了,否则会RE

为什么

救我

开数组已经是100倍了,100000就够,我开了10000000都不行

 

转载于:https://www.cnblogs.com/znsbc-13/p/11198928.html

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