【队列】用双向链表加队列实现窗口查询问题

//双向链表模拟队列
#include 
#include 
using namespace std;
queuemy_queue;

class Node
{
public:
	int element;
	Node* pre;
	Node* next;

	Node()
	{
		pre = nullptr;
		next = nullptr;
	}
};

class Listnode
{
public:
	Node* listnode;
	Node* rear;
	int count = 0;

	Listnode();

	void En_listnode(int x);
	void De_listnode(int x);
	void Print_max();
	bool Is_empty();
	void Print_listnode();
};

Listnode::Listnode()
{
	count = 0;
	listnode = new Node;
	listnode->next = nullptr;
	listnode->pre = nullptr;
}

bool Listnode::Is_empty()
{
	if (count == 0)
	{
		return true;
	}
	else
		return false;
}

void Listnode::En_listnode(int x)
{
	if (Is_empty()==true)
	{
		Node* ptr = new Node;
		ptr->element = x;
		ptr->pre = listnode;
		listnode->next = ptr;
		rear = ptr;
		count++;
		return;
	}
	else
	{
		Node* temp = new Node;
		temp->pre = rear;
		temp->element = x;
		rear->next = temp;
		temp->next = nullptr;
		

		while (x > rear->element)
		{
			temp->pre = rear->pre;
			rear->pre->next = temp;
			delete rear;
			rear = temp;
		}
		rear = temp;
		temp = nullptr;
		return;
	}

}

void Listnode::De_listnode(int x)
{
	if (listnode->next->element == x)
	{
		Node* temp = listnode->next;
		
		listnode->next = listnode->next->next;
		listnode->next->pre = listnode;
		delete temp;
		return;
	}
}

void Listnode:: Print_max()
{
	cout << "这个窗口最大的数是" << listnode->next->element << endl;
}

void Listnode::Print_listnode()
{
	Node* ptr = listnode->next;
	while (ptr)
	{
		cout << ptr->element << " ";
		ptr = ptr->next;
	}
	cout << endl;

}


int main()
{
	Listnode my_listnode;
	int arr[100];
	cout << "请问窗口大小为多少" << endl;
	int window_size = 0;
	cin >> window_size;

	cout << "请问一共输入多少个数据" << endl;
	int data_size;
	cin >> data_size;

	cout << "开始输入数据" << endl;
	for (int i = 0; i < data_size; i++)
	{
		cin >> arr[i];
	}

	int time = data_size - window_size;
	cout << "一共移动" << time << "次" << endl;

	for (int i = 0; i < window_size; i++)
	{
		my_queue.push(arr[i]);
		my_listnode.En_listnode(arr[i]);
	}
	my_listnode.Print_max();
	for (int i = window_size; i < time+window_size; i++)
	{
		my_queue.push(arr[i]);
		int temp = my_queue.front();//此时出列的元素
		my_queue.pop();
		my_listnode.En_listnode(arr[i]);
		my_listnode.De_listnode(temp);
		my_listnode.Print_max();
	}


	return 0;


}

算法复杂度 比每次滑动都重新判断一次要简单，这也是优势之一，但是代码量较多