js 简单的请求XMLHttpRequest

简单的请求XMLHttpRequest
  // 发送请求
      let xhr = new XMLHttpRequest()
      xhr.open('get', domainURL + '/dc/repay-gold/lottie/0301redPacket/surprise.json')
      xhr.onreadystatechange = () => {
        if (xhr.readyState === 4 && xhr.status === 200) {
          // 返回的结果
          xhr.responseText
        }
      }
      xhr.send()